A particle is moving with the given data. Find the position of the particle. a(t) = 2t + 9, s(0) = 8, v(0) = −7

1 answer:

4 0

If you mean by a(t)=2t+9 is the acceleration function then we integrate...

v(t)=2t^2/2+9t+c where c is vo and we are told that that is -7 so

v(t)=t^2+9t-7 integrating again we get:

s(t)=t^3/3+9t^2/2-7t+c where c is the initial position which is 8 so

s(t)=t^3/3+9t^2/2-7t+8 which neatened up as

s(t)=(2t^3+27t^2-42t+48)/6

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Answer:

Option C, $y = \frac{1}{10} x+1$

Step-by-step explanation:

We can find the correct answer by plugging in the x and y values of a point on the graph into each option, then finding the one that gives a true statement as a result.

For example, one point on the graph is (30,4). We can substitute 30 for the x and 4 for the y in option C's equation, $y = \frac{1}{10} x+1$ . Then, simplify:

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