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4 years ago

How to do a exponent with the negative base?

2 answers:

tatiyna4 years ago

3 0

Examples :
(-2)^3 = (-2)(-2)(-2) = - 8

(-3)^4 = (-3)(-3)(-3)(-3) = 81

(-1)^5 = (-1)(-1)(-1)(-1)(-1) = -1

** if the exponent is an even number, the answer will be positive. if the exponent is an odd number, then the answer will be negative

** but keep in mind....if the negative is not included with the base..
-(5^2) = - 25....but (-5^2) = 25

Sergeeva-Olga [200]4 years ago

3 0

Any number raised to a negative exponent could be written as follows:

a⁻ⁿ = 1/aⁿ

a⁻² = 1/a²

a⁻²³ = 1/a²³

a⁻ˣ = 1/aˣ

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A bacteria culture starts with 100 bacteria and doubles in size every half hour.

taurus [48]

Answer:

y=25600

y=100(2)^{2t}

y=252

Step-by-step explanation:

A bacteria culture starts with 100 bacteria and doubles in size every half hour.

$y=100(2)^{2x}$

where x represents the number of hours

(a) t= 4 hours

Plug in 4 for t and find out the number of bacteria y

$y=100(2)^{2 \cdot 4}\\y=25600$

25600 bacteria

$y=100(2)^{2t}$

convert 40 seconds into hour

40 divide by 60 =2/3

$y=100(2)^{2\frac{2}{3} }\\y=100(2)^{\frac{4}{3} }\\\\y=252$

The graph is attached below

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LenKa [72]

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Step-by-step explanation:

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3 years ago

Solve for r. –7r = –8r − 20 r =

attashe74 [19]

Answer:

r = -20

Step-by-step explanation:

–7r= –8r−20

Add 8r to both sides

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3 years ago

Read 2 more answers

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3 years ago

Find the length of each side of the triangle determined by the three points P1,P2, and P3. State whether the triangle is an isos

Tanya [424]

Answer:

The triangle is both an Isosceles triangle and a right triangle.

Step-by-step explanation:

Given the vertices of a triangle.

$P_{1} = (- 1, 4)$

$P_{2} = (6, 2)$ and

$P_{3} = (4, - 5)$

We find the distance between all the points to determine the length of each side of the triangle.

Distance between any two points, say, $(x_1, y_1)$ and $(x_2, y_2)$ is:

$\sqrt{\bigg ( \textbf{x}_{\textbf{2}} \hspace{1mm} \textbf{- x}_{\textbf{1}} \bigg )^{\textbf{2}} \textbf{+} \bigg( \textbf{y}_{\textbf{2}} \hspace{1mm} \textbf{- y}_{\textbf{1}} \bigg)^ {\textbf{2}}$