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3 years ago

Please help me please please please please

Mathematics

2 answers:

vivado [14]3 years ago

5 0

3.625/15
This is the answer

sergey [27]3 years ago

4 0

The Answer Is 0

I Hope This Helped!

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Write the equation of the line that passes through the point (-3, -1) with a slope of -2/3

svp [43]

-1=-2/3(-3) + b

-1=2 + b

b=-3

Y= -2/3x -3

4 0

3 years ago

The length of rectangle is represented by 8x - 3. The width of the rectangle is represented by 2x. The perimeter is 34 inches. W

Strike441 [17]

Answer: 20x-6 = 34

Step-by-step explanation:

Given: The length of rectangle is represented by 8x - 3.

The width of the rectangle is represented by 2x.

The perimeter is 34 inches.

Perimeter of rectangle = 2 (length + width)

Perimeter of rectangle = 2 (8x-3+2x)

Perimeter of rectangle = 2 (10x-3)

Perimeter of rectangle = 20x-6

Thus , the required equation that represent the perimeter: 20x-6 = 34

8 0

3 years ago

Help help , Please help! Brainliest if correct! What was the equation of the graph below before it was shifted to the left 1.5 u

DENIUS [597]

Answer:

A. G(x) = (x -3)^3 -(x -3)

Step-by-step explanation:

The graph before it was shifted left will be a right-shift of the equation shown. That is accomplished by replacing x with (x-1.5). Then the right-shifted equation is ...

G(x) = ((x-1.5) -1.5)^3 -((x -1.5) -1.5)

G(x) = (x -3)^3 -(x -3) . . . . matches choice A

3 0

3 years ago

A cylinder is placed within a cube. The diameter of the cylinder is equal to the length of each side of the cube. What is the vo

pochemuha

The volume of a shape is the amount of space in it.

<em>The volume outside the cylinder, but inside the cube is 214.6 cubic inches</em>

The given parameter is:

$l = 10$ ---- length of the cube

So, the volume of the cube is:

$V_1 = l^3$

$V_1 = 10^3$

$V_1 = 1000$

The volume of the cylinder is:

$V_2 = \pi r^2h$

The diameter (d) of the cylinder equals the length of the cube.

This means that:

$d = l$

$d = 10$

Divide by 2 to calculate the radius of the cylinder

$r = \frac{10}{2}$

$r = 5$

Also, the height of the cube is::

$h =l$

$h =10$

So, we have:

$V_2 = \pi r^2h$

$V_2 = \pi \times 5^2 \times 10$

$V_2 = \pi \times 25 \times 10$

$V_2 = \pi \times 250$

$V_2 = 785.4$

So, the volume (V) outside the cylinder is:

$V = V_1 - V_2$

$V = 1000 - 785.4$

$V = 214.6$

Hence, the volume outside the cylinder is 214.6 cubic inches