Bonus #1) June 30 is equivalent to the 91st day of April or the 61st day of May.
Hilda's deposit of 4520 earned interest for 91-1 = 90 days.
Hilda's deposit of 580 earned interest for 61-10 = 51 days.
Hilda's deposit of 590 earned interest for 61-23 = 38 days.
Balance = $4520·(1 +.035/365)⁹⁰ + 580·(1 +.035/365)⁵¹ + 590·(1 +.035/365)³⁸
... = $4559.175 +582.843 +592.154
... ≈ $5734.17
Deposits total 4520 +580 +590 = 5690, so interest earned is
... $5734.17 -5690.00 = $44.17
Bonus #2) This problem can be worked the same way, except that withdrawals are subtracted from the final balance.
Owner's deposit of $12,300 earned interest for 91 days.
Owner's withdrawal of $3600 reduced the balance for 53 days.
Owner's withdrawal of $1200 reduced the balance for 10 days.
Balance = $12300·(1 +.035/365)⁹¹ -3600·(1 +.035/365)⁵³ -1200·(1 +.035/365)¹⁰
... = $12,407.795 -3618.342 -1201.151
... ≈ $7588.30
Interest earned = $7588.30 - (12300 -3600 -1200) = $88.30
Answer:
Step-by-step explanation:
From the given question.
We can write the null hypothesis & the alternative hypothesis as:
Null hypothesis:
Alternative hypothesis:
From above, let's think about the type I error we could make and the type II error we could make.
<u>Type I error:</u>
The type I error at the null hypothesis showcases that the snow level is at 6 inches or below 6 inches, but we falsely concluded that the snow level is high above sea level.
<u>Type II error:</u>
Here, the snow level is literally above 6 inches, hence, we failed to conclude that the snow level is above 6 inches.
Thus, the consequences of the above analysis showcase that type II error has higher severe consequences because it may result in a situation that may endanger the passengers' safety.
I’m pretty sure the answer is b but not 100%
Answer:
x > -1
Step-by-step explanation:
Simplify the inequality using the distributive property (multiply the term outside the bracket with each number inside the bracket). Then, isolate 'x' by performing the reverse operations for every number that's on the same side as 'x'. (Reverse operations 'cancel out' a number.)
18 < -3(4x - 2) Expand this to simplify
18 < (-3)(4x) - (-3)(2) Multiply -3 with 4x and -2
18 < -12x + 6 Start isolating 'x'
18 - 6 < -12x + 6 - 6 Subtract 6 from both sides
18 - 6 < -12x '+ 6' is cancelled out on the right side
12 < -12x Subtracted 6 from 18 on the left side
12/-12 < -12x/-12 Divide both sides by -12
12/-12 < x 'x' is isolated. Simplify left side
-1 < x Answer
x > -1 Standard formatting puts variable on the left side
Two events are occurring:
1) Rolling a die
Sample Space = {1,2,3,4,5,6}
Total number of outcomes in sample space = 6
Favorable outcomes = Odd number
Number of Favorable outcomes = 3
Probability of getting an odd number = 3/6
2) Tossing a coin
Sample Space = {H, T}
Probability of getting a head= 1/2
The probability of getting odd number and head will be the product of two probabilities, which will be = 3/6 x 1/2 = 3/12
Thus there is 3/12 = 1/4 (0.25 or 25%) probability of getting an odd number and a head in given scenario.
So correct answer is option C
