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sasho [114]
3 years ago
12

If the sample size is multiplied by 4, what happens to the standard deviation of the distribution of sample means?

Mathematics
1 answer:
Feliz [49]3 years ago
6 0

Increasing the sample size by a factor of 4 or multiplying it by 4 is equal to increasing the standard error by 1/2.  Therefore, the interval will be half as varied.  This also works almost for population averages as lengthy as the multiplier from the t-curve doesn't modify much when increasing the sample size.

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Write an exponential function in the form y = ab that goes through points (0,4)<br> and (2, 196).
yawa3891 [41]

Answer:

y = 4(7)^{x}

Step-by-step explanation:

The form of the exponential function is y = a b^{x}

Use the given points to solve for a and b

Using (0, 4 ), then

4 = ab^{0} ( b^{0} = 1 ), thus a = 4

y = 4 b^{x}

Using (2, 196 ), then

196 = 4b² ( divide both sides by 4 )

49 = b² ( take the square root of both sides )

b = \sqrt{49} = 7

y = 4(7)^{x} ← exponential function

6 0
3 years ago
Choose a method . Then find the product 10x15
34kurt

Answer:

150

Step-by-step explanation:

15*10

Lets get rid of the 0 for now

15*1

That is 15 added to itself 0 times so it is 15

Now lets put the 0 back

and we will get

150

5 0
3 years ago
Read 2 more answers
Find the compound interest on 50000 for 9 month at 8 %
Ahat [919]

Answer:The answer is 5, 414.52

Step-by-step explanation:

Since number of years isn't imputed, it will be assumed it's for 1 year

Hence using Compound interest formula

A = P( 1 + r/n)^not

Inputting values

A = 5000( 1 + 0.08/9) ^ 9*1

A = 5, 414.52

Hope this helps

7 0
3 years ago
Help you will get brainliest
victus00 [196]

Answer:

4.25

Step-by-step explanation:

7 0
3 years ago
Two vectors A⃗ and B⃗ are at right angles to each other. The magnitude of A⃗ is 5.00. What should be the length of B⃗ so that th
creativ13 [48]

Answer:

Length of B is 7.4833

Step-by-step explanation:

The vector sum of A and B vectors in 2D is

C=A+B=(a_1+b_1,a_2+b_2)

And its magnitude is:

C=\sqrt{(a_1+b_1)^2+(a_2+b_2)^2} =9

Where

a_1=Asinx

a_2=Acosx

b_1=Bsin(x+90)

b_2=Bcos(x+90)

Using the properties of the sum of two angles in the sin and cosine:

b_1=Bsin(x+90)=B(sinx*cos90+sin90*cosx)=Bcosx

b_2=Bcos(x+90)=B(cosx*cos90-sinx*sin90)=-Bsinx

Sustituying in the magnitud of the sum

C=\sqrt{(Asinx+Bcosx)^2+(Acosx-Bsinx)^2} =9

C=\sqrt{A^2sin^2x+2ABsinxcosx+B^2cos^2x+A^2cos^2x-2ABsinxcosx+B^2sin^2x} =9

C=\sqrt{A^2(sin^2x+cos^2x)+B^2(cos^2x+sin^2x)}

C=\sqrt{A^2+B^2} =9

Solving for B

A^2+B^2 =9^2

B^2 =9^2-A^2

Sustituying the value of the magnitud of A

B^2=81-5^2=81-25=56

B= 7. 4833

8 0
3 years ago
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