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Komok [63]
3 years ago
5

A tank has a capacity of 10 gallons. When it is full it contains 15% alcohol. How many gallons must be replaced by an 80% soluti

on to goive 10 gallons of a 70% solution?
Mathematics
1 answer:
PIT_PIT [208]3 years ago
5 0

Answer:

8.46 gallons needed to be replaced

Step-by-step explanation:

Let x be the alcohol amount that replaced

-Original has concentration of 15% multiply by the amount of 10 ,which is equal to (0.15×10).

-Removed has concentration of 15% multiply by the amount of x ,which is equal to (0.15 × X).

-Added has concentration of 80% multiply by the amount of X ,which is equal to (0.8× X).

-Solution has concentration of 70% multiply by the amount of 10 ,which is equal to (0.70×10).

So that, the equation will be:

Solution=Original + added - removed

7=1.5+0.8x-0.15x

7-1.5=0.65x

0.65x=55

x=55/0.65

x=8.46

8.46 gallons needed to be replaced.

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Answer:

The farmer have at first <u>202</u> chickens.

Step-by-step explanation:

Given:

A farmer had twice as many chickens as ducks on his farm. After he sold 166 chickens and ducks, he had half as many chickens as ducks left.

Now, to find the chickens farmer have at first.

Let the chickens be x.

And, the ducks be y.

<em>As, the farmer had twice as many chickens as ducks on his farm.</em>

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<em>As, given the farmer after selling 166 chickens and ducks, he had half as many chickens as ducks left.</em>

According to question:

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x-166=\frac{y-29}{2}

Substituting the value of x from equation (1) we get:

2y-166=\frac{y-29}{2}

<em>By cross multiplying we get:</em>

4y-332=y-29

<em>Adding both sides 332 we get:</em>

4y=y+303

<em>Subtracting both sides by </em>y<em> we get:</em>

3y=303

<em>Dividing both sides by 3 we get:</em>

y=101.

Now, to get the number of chickens substituting the value of y in equation (1):

x=2y\\\\x=2\times 101\\\\x=202.

Therefore, the farmer have at first 202 chickens.

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