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borishaifa [10]
3 years ago
15

Match the sequence (term) with the correct type of sequence (definition). match term definition 128, 32, 8, 2, …

Mathematics
1 answer:
Temka [501]3 years ago
8 0
Note that we can get 32 from 128 by mult. 32 by (32/128), or (1/4).  Mult. 32 by (1/4) produces the 3rd term, 8, as expected.  Thus, the common ratio, r, is 1/4.

Illustrations:

128(1/4) = 32
32(1/4) = 8
8(1/4) =2
2(1/4) = 1/2
and so on.

This is a geometric series with first term 128 and common ratio 1/4.

None of the 4 possible answers you've shared matches this outcome.  Check to ensure that you've copied them down accurately.  But most importantly, decide whther or not you agree that the common ratio of the given sequence is 1/4 and that the first term is 128.

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One equation in a system of equations is y = 3/4x - 1. For which second equation would the system have exactly one solution? cho
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Answer:

ace

Step-by-step explanation:

5 0
3 years ago
Find the quotient of 48a^4-16a^2-32/8a^2-8
Novay_Z [31]
We know that if we had
8/6=2/2 times 4/3=1 times 4/3=4/3
find common factors in top and obttom
factor
48a^4-16a^2-32=(16)(a-1)(a+1)(3a^2+2)
8a^2-8=8(a-1)(a+1)
so we have
\frac{48a^4-16a^2-32}{8a^2-8} = \frac{(2)(8)(a-1)(a+1)(3a^2+2)}{(8)(a-1)(a+1)}= (\frac{8}{8}) (\frac{a-1}{a-1})( \frac{a+1}{a+1}) ( \frac{(2)(3a^{2}+2)}{1})=(2)(3a^2+2)=6a^2+4


answer is 6a^2+4
5 0
3 years ago
B(h+w)=4h(11-j), solve for w
frozen [14]

Answer:

W=4h(11-j)/b-h

Step-by-step explanation:

Eliminate variables on the left side first.

b(h+w) = 4h (11-j) - so, divide b by both sides

(h+w)/b=4h(11-j)/b  then, eliminate h by subtracting on both sides.

(h+w)-h=4h(11-j)/b - h   (h is eliminated on the left side and now you are left with

W=4h(11-j)/b - h

   

4 0
3 years ago
3(5b-1)=5<br> solve for b<br><br> 4(3y-1)=20<br> solve for y
Gnom [1K]
3(5b-1)=5
Get rid of the brackets
15b-3=5
add 3 to both sides of the equation
15b=8
divide both sides of the equation by 15
b=0.53

4(3y-1)=20
12y-4=20
12y=24
y=0.5
7 0
3 years ago
For questions 4-5, decide whether each table of values describes a function or not.
lara31 [8.8K]

Answer:

Function

Step-by-step explanation:

Two different X's could equal the same Y value so this is a function. Remember if there's multiple of the same input (x) equalling different outputs (y) then it is not a function. If there's multiple inputs (x) equalling the same output (y) it's just coincidence and works.

3 0
3 years ago
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