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Radda [10]
3 years ago
9

Please help me smart people!!!!! It would be realllllyyyyy helpful right now!!!!!!

Mathematics
1 answer:
Bumek [7]3 years ago
8 0
9. 2/6 and in simplified form it’s 1/3
10. 10/4 simplified is 5/2
11. 8/2 simplified is 4/1
12. 7/7 which is 1
13. Has no slope
14. 4/7
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A 1 liter bottle of orange juice used to cost 2.85 at food market it’s price has increased the new price is 110 precent of the o
jeyben [28]

Answer:

2.85*100divid 110

Step-by-step explanation:


3 0
3 years ago
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The ratio of vowels to consonants in a word is 5 to 7. Are there more vowels or consonants in the word?
lbvjy [14]
If the ratio is 5-7... this means there are more consonants
3 0
3 years ago
What is the area??????
Westkost [7]
Your answer would be 91.1 units².
We can split this shape into a trapezium and a semicircle, and then find the area of both and add them.
To find the area of a trapezium, the formula is
(a + b)/2 × h, which means we do 14 (the length of AD) + 8 (the length of BC) = 22, and 22/2 = 11. Then we multiply 11 by the height of the trapezium, which is 6 because 10 - 4 = 6. This gives us the area of the trapezium as 66 units².
To find the area of a semicircle, the formula is πr²/2, and the radius is 4 because the diameter is 8 (16 - 8 = 8). This means we do π4²/2 = 16π\2 = 8π = 25.13.
Then we need to add together 66 and 25.13, which equals 91.13, or 91.1 to the nearest tenth.
I hope this helps!
7 0
3 years ago
Read 2 more answers
The weights of adult male birds of a certain species are normally distributed with a mean of 27.5 grams and a standard deviation
Korvikt [17]

Answer:

The z-score of a male bird of this species with a weight of 29.37 grams is 1.7.

Step-by-step explanation:

We are given that the weights of adult male birds of a certain species are normally distributed with a mean of 27.5 grams and a standard deviation of 1.1 grams.

<u><em>Let X = weights of adult male birds of a certain species</em></u>

So, X ~ Normal(\mu=27.5,\sigma^{2} =1.1^{2})

The z score probability distribution for normal distribution is given by;

                                 Z = \frac{ X-\mu}{\sigma } }  ~ N(0,1)

where, \mu = population mean weight = 27.5 grams

           \sigma = standard deviation = 1.1 grams

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

SO, the z-score of a male bird of this species with a weight of 29.37 grams is given by;

          <u>Z score</u> =  \frac{ X-\mu}{\sigma } } = \frac{ 29.37-27.5}{1.1 } }

                                    =  <u>1.7</u>

                       

4 0
2 years ago
What is the gcf of 6 and 14​
Tamiku [17]

Answer:

2

Step-by-step explanation:

because their gretest common factor is 2

3 0
3 years ago
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