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3 years ago

Please help me smart people!!!!! It would be realllllyyyyy helpful right now!!!!!!

Mathematics

1 answer:

Bumek [7]3 years ago

8 0

9. 2/6 and in simplified form it’s 1/3
10. 10/4 simplified is 5/2
11. 8/2 simplified is 4/1
12. 7/7 which is 1
13. Has no slope
14. 4/7

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Simplify the expression <br> -7(3e-2f+4)+6e-2

Shkiper50 [21]

Answer: here it is 14f-30-15e

5 0

3 years ago

The basketball team has 50 members, and 18 of them are 6th graders. What percentage of the team is in the 6th grade?

motikmotik

Answer:

36%

Step-by-step explanation:

$\frac{18}{50} = \frac{36}{100}$

So 36% of the team is in 6th grade.

8 0

3 years ago

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A map uses a scale of 3/4 in = 80 miles. If two buildings are 60 miles apart in real life, how far apart would they be drawn on

Alla [95]

Given:

The scale of a map is $\dfrac{3}{4}\ in=80\ miles$ .

The distance between two buildings is 60 miles.

To find:

The distance between the given building on the map.

Solution:

We have,

$\dfrac{3}{4}\ in=80\ miles$

It means, 80 miles in real life = $\dfrac{3}{4}\ in$ on the map.

1 mile in real life = $\dfrac{3}{4\times 80}\ in$ on the map.

60 mile in real life = $\dfrac{3\times 60}{4\times 80}\ in$ on the map.

= $\dfrac{180}{320}\ in$ on the map.

= $\dfrac{9}{16}\ in$ on the map.

Therefore, the buildings are $\dfrac{9}{16}\ in$ apart on the map.

7 0

2 years ago

A company manufactures running shoes and basketball shoes. The total revenue (in thousands of dollars) from x1 units of running

Alborosie

Answer:

$x_1 =2 , x_2=7$

Step-by-step explanation:

Consider the revenue function given by $R(x_1,x_2) = -5x_1^2-8x_2^2 -2x_1x_2+34x_1+116x_2$ . We want to find the values of each of the variables such that the gradient( i.e the first partial derivatives of the function) is 0. Then, we have the following (the explicit calculations of both derivatives are omitted).

$\frac{dR}{dx_1} = -10x_1-2x_2+34 =0$

$\frac{dR}{dx_2} = -16x_2-2x_1+116 =0$

From the first equation, we get, $x_2 = \frac{-10x_1+34}{2}$ .If we replace that in the second equation, we get

$-16\frac{-10x_1+34}{2} -2x_1+116=0= 80x_1-2x_1+116-272= 78x_1-156$

From where we get that $x_1 = \frac{156}{78}=2$ . If we replace that in the first equation, we get

$x_2 = \frac{-10\cdot 2 +34}{2}=\frac{14}{2} = 7$

So, the critical point is $(x_1,x_2) = (2,7)$ . We must check that it is a maximum. To do so, we will use the Hessian criteria. To do so, we must calculate the second derivatives and the crossed derivatives and check if the criteria is fulfilled in order for it to be a maximum. We get that

$\frac{d^2R}{dx_1dx_2}= -2 = \frac{d^2R}{dx_2dx_1}$

$\frac{d^2R}{dx_{1}^2}=-10, \frac{d^2R}{dx_{2}^2}=-16$

We have the following matrix,

$\left[\begin{matrix} -10 & -2 \\ -2 & -16\end{matrix}\right]$ .

Recall that the Hessian criteria says that, for the point to be a maximum, the determinant of the whole matrix should be positive and the element of the matrix that is in the upper left corner should be negative. Note that the determinant of the matrix is $(-10)\cdot (-16) - (-2)(-2) = 156>0$ and that -10<0. Hence, the criteria is fulfilled and the critical point is a maximum

8 0

3 years ago

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A baseball stadium sold some burgers. 2,806 were cheeseburgers. 1,679 burgers didn’t have cheese. How many burgers did they sell

kodGreya [7K]

Answer:

4485

Step-by-step explanation:

1679+2806= 4485

Hope this helps! :)

7 0

2 years ago