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2 years ago

Divide (18x^3 + 12x – 3x) ÷ 6x^2

1 answer:

4 0

First let's simplify it

$\frac{18x^3 + 9x}{6x^2}$

Now let's factor it
$\frac{9x(2x^2 + 1)}{6x^2}$

Lastly, let's simplify
$\frac{3(2x^2 + 1)}{2x}$

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Least to greatest 1.1,0.138,1.412,and 1.414213

gizmo_the_mogwai [7]

Least to greatest:

0.138, 1.1, 1.412, 1.414213.

5 0

2 years ago

How would you write the following expression as a sum or difference? `"log"(root(3)(2 - x)/(3x))`

pashok25 [27]

<h3>Further explanation</h3>

Let's recall following formula about Exponents and Surds:

$\boxed { \sqrt { x } = x ^ { \frac{1}{2} } }$

$\boxed { (a ^ b) ^ c = a ^ { b . c } }$

$\boxed {a ^ b \div a ^ c = a ^ { b - c } }$

$\boxed {\log a + \log b = \log (a \times b) }$

$\boxed {\log a - \log b = \log (a \div b) }$

<em>Let us tackle the problem!</em>

$\texttt{ }$

$\log \frac{\sqrt{3}(2-x)}{(3x)} = \log \sqrt{3} + \log (2-x) - \log (3x)$

$\log \frac{\sqrt{3}(2-x)}{(3x)} = \log 3^{1/2} + \log (2-x) - (\log 3 + \log x)$

$\log \frac{\sqrt{3}(2-x)}{(3x)} = \frac{1}{2} \log 3 + \log (2-x) - \log 3 - \log x$

$\log \frac{\sqrt{3}(2-x)}{(3x)} = \log (2-x) - \frac{1}{2}\log 3 - \log x$

$\texttt{ }$

<h3>Learn more</h3>

Coefficient of A Square Root : brainly.com/question/11337634
The Order of Operations : brainly.com/question/10821615
Write 100,000 Using Exponents : brainly.com/question/2032116

<h3>Answer details</h3>

Grade: High School

Subject: Mathematics

Chapter: Exponents and Surds

Keywords: Power , Multiplication , Division , Exponent , Surd , Negative , Postive , Value , Equivalent , Perfect , Square , Factor.

7 0

3 years ago

Solve this identifying holes, vertical asymptotes, and horizontal asymptotes for

USPshnik [31]

$x^2+7x+12=x^2+4x+3x+12=x(x+4)+3(x+4)=(x+4)(x+3)\\\\-x^2-3x+4=-(x^2+3x-4)=-(x^2+4x-x-4)\\\\=-[x(x+4)-1(x+4)]=-(x+4)(x-1)\\\\f(x)=\dfrac{x^2+7x+12}{-x^2-3x+4}=\dfrac{(x+4)(x+3)}{-(x+4)(x-1)}\\\\\text{Vertical asymptotes:}\\\\(x+4)(x-1)=0\iff x+4=0\ \vee\ x-1=0\\\\\boxed{x=-4\ and\ x=1}\\\\\text{Horizontal asymptotes:}$

$\lim\limits_{x\to\pm\infty}\dfrac{x^2+7x+12}{-x^2-3x+4}=\lim\limits_{x\to\pm\infty}\dfrac{x^2\left(1+\dfrac{7}{x}+\dfrac{12}{x^2}\right)}{x^2\left(-1-\dfrac{3}{x}+\dfrac{4}{x^2}\right)}=\dfrac{1}{-1}=-1\\\\\boxed{y=-1}$

6 0

3 years ago

NEED HELP ASAP

Aliun [14]

Well, first you want to figure out how many sentences Jolie has left to read. You can do that by multiplying 120 by 17 which equals 2,040. Then you have to divide 2,040 by 14. The answer to that is about 145.72 which you could just leave at about 145 minutes. And to simplify that even more you could divide by 60 and figure that 145.72 is about 2 hours and 42 minutes.

3 0

3 years ago

In the first few weeks of the season, a basketball player averaged 27 points per game. Then the player was on a streak. The tab

vovikov84 [41]

Answer:

1.5

Step-by-step explanation:

3 0

2 years ago

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