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qaws [65]
3 years ago
6

10. Given f(x) = 2x + 8 which points are

Mathematics
1 answer:
Bingel [31]3 years ago
4 0

Answer:

It would be B and C

Step-by-step explanation:

When you substitute the numbers on choice B you get something as follows

f(x)=2(-1)+8

f(x)=-2+8

f(x)=6, therefore

(-1,6)

you can also do the same step for C

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Type the correct answer in each box. If necessary, use / for the fraction bar. A bag contains 5 blue marbles, 2 black marbles, a
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Answer:

Step-by-step explanation:

Problem One

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Black  =2

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First of all there are 10 marbles, 2 of which are black.

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You can draw any one of the 8.

P(not black) = 8/10 = 4/5

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There are 10 marbles in all

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1<br> Find the slope of the following graph and write your result in the empty box.<br> Answer:
Viktor [21]

Answer:

y = 2x

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2 years ago
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8 0
3 years ago
Is sin theta=5/6, what are the values of cos theta and tan theta?
mina [271]

let's bear in mind that sin(θ) in this case is positive, that happens only in the I and II Quadrants, where the cosine/adjacent are positive and negative respectively.

\bf sin(\theta )=\cfrac{\stackrel{opposite}{5}}{\stackrel{hypotenuse}{6}}\qquad \impliedby \textit{let's find the \underline{adjacent side}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{6^2-5^2}=a\implies \pm\sqrt{36-25}\implies \pm \sqrt{11}=a \\\\[-0.35em] ~\dotfill

\bf cos(\theta )=\cfrac{\stackrel{adjacent}{\pm\sqrt{11}}}{\stackrel{hypotenuse}{6}} \\\\\\ tan(\theta )=\cfrac{\stackrel{opposite}{5}}{\stackrel{adjacent}{\pm\sqrt{11}}}\implies \stackrel{\textit{and rationalizing the denominator}~\hfill }{tan(\theta )=\pm\cfrac{5}{\sqrt{11}}\cdot \cfrac{\sqrt{11}}{\sqrt{11}}\implies tan(\theta )=\pm\cfrac{5\sqrt{11}}{11}}

5 0
3 years ago
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