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babymother [125]
3 years ago
10

The first sequence rule is multiply by 2 starting from 6. The second sequence rule is add 4 starting from 16. What is the first

number that appears in both sequences?
12
16
24
48
Mathematics
2 answers:
KiRa [710]3 years ago
3 0
The answer is 24
6*2=12*2=24
16+4=20+4=24
mixas84 [53]3 years ago
3 0

Answer:

24

Step-by-step explanation:

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32

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Step-by-step explanation:

8 0
3 years ago
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Write an equation of a line containing (2, 1) and (3, 4) in point-slope form.
ivann1987 [24]

Answer:

y-1=3(x-2)

Or

y-4=3(x-3)

Step-by-step explanation:

The slope formula is given by:

m=\frac{y_2-y_1}{x_2-x_1}

The line containing (2, 1) and (3, 4)  has slope;

m=\frac{4-1}{3-2}=3

The point-slope form is given by:

y-y_1=m(x-x_1)

We substitute the point and slope to get:

y-1=3(x-2)

Or

y-4=3(x-3)

8 0
4 years ago
Sarah kept track of the points she scored during her first five basketball games in the table shown.
grandymaker [24]

Answer:

E

Step-by-step explanation:

If you add 22 onto the sum of all the points and divide by the amount of games (6), you get 12.

4 0
3 years ago
4x−3y=18 Step 2 of 2 : Determine the missing coordinate in the ordered pair (?,12) so that it will satisfy the given equation.
Natasha_Volkova [10]

Answer:

13.5

Step-by-step explanation:

The point with the missing coordinate is (?, 12), so the value of  y  is 12.  Plug 12 into the equation in the place of  y.

4x - 3(12) = 18

4x - 36 = 18

4x = 54

x = 54/4 = 13.5

3 0
2 years ago
Show the region which satisfies simultaneously the inequalities 2x+3y≤8, x-2y≥-3, x≥0, y≥0
Verizon [17]
The first thing you should do is graph the following lines
 2x + 3y = 8
 x-2y = -3
 x = 0
 y = 0
 After you have graphed them, you should proceed to evaluate points in the xy plane that meet the following restrictions:
 2x + 3y≤8, x-2y≥-3, x≥0, y≥0
 The resulting region is the region "R" shown in the attached graph.

8 0
3 years ago
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