Evaluate the expression s=5 and t=7. 3st to the second power is what
1 answer:
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Answer:
-
or -+8x-16
Step-by-step explanation:
Given a second degree polynomial has a root 4 with multiplicity 2
That means, 4 is a repeating root of the polynomial.
Any second degree polynomial has at most 2 real roots.
⇒Both roots of the polynomial are 4.
and its expression can be written as c· where c is a real number
⇒c·(-8x+16)
⇒c-8cx+16c
Also, the leading coefficient is given as -1
So, c = -1
and the expression becomes (-1)-8·(-1)·x+16·(-1)
⇒<u>-+8x-16</u>
Given:
The equation of a circle is:
To find:
Center and the circumference of the circle.
Solution:
The standard form of a circle is:
...(i)
Where, (h,k) is center and r is the radius.
We have,
...(ii)
On comparing (i) and (ii), we get
So, the center of the circle is (3,0) and the radius of the circle is .
Now, the circumference of the circle is:
Therefore, the circumference of the circle is about 35.5 units.