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Sunny_sXe [5.5K]
3 years ago
9

Which second degree polynomial function has a leading coefficient of –1 and root 4 with multiplicity 2?

Mathematics
1 answer:
Fynjy0 [20]3 years ago
7 0

Answer:

-(x-4)^{2}

or -x^{2}+8x-16

Step-by-step explanation:

Given a second degree polynomial has a root 4 with multiplicity 2

That means, 4 is a repeating root of the polynomial.

Any second degree polynomial has at most 2 real roots.

⇒Both roots of the polynomial are 4.

and its expression can be written as c·(x-4)^{2} where c is a real number

⇒c·(x^{2}-8x+16)

⇒cx^{2}-8cx+16c

Also, the leading coefficient is given as -1

So, c = -1

and the expression becomes (-1)x^{2}-8·(-1)·x+16·(-1)

⇒<u>-x^{2}+8x-16</u>

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<h2>Answer:</h2>

The total number of handshakes that would happen between the three people are:

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<h2>Step-by-step explanation:</h2>

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Let they be denoted by A,B and C.

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and BC denote that B and C shake hands.

Hence, total number of handshakes are:

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Which situation could the expression 1/4 ÷ 3 represent?
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bogdanovich [222]

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Hope this helped you! :)

-Peredhel

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