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3 years ago

I need to know who to solve number 27

Mathematics

1 answer:

miskamm [114]3 years ago

5 0

F=9/5C+32
-9/5C+F=32
-9/5C=-F+32
C=9/5F-57.6

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Find the area of this triangle, round to the nearest tenth, I will give brainliest

Setler79 [48]

Answer:

59.15 in^2

Step-by-step explanation:

Using Heron's formula

semiperimeter , s = 1/2 ( 28.8+18+12) = 29.4

Area = sqrt ( 29.4(29.4-28.8)(29.4-18)(29.4-12) ) = 59.15 in^2

4 0

2 years ago

Read 2 more answers

This one too please!!!!!!!!!

Vinvika [58]

X= 0 and 1 are the answers

7 0

3 years ago

I need help with both questions on the screen. if you can only answer one thats fine too!

meriva

Answer:

11. $b = 30$

Step-by-step explanation:

$a^{2} + b^{2} = c^{2}$

Substitute

$16^{2} + b^{2} = 34^{2}$

$256 + b^2 = 1156$

$b^2 = 1156-256\\b^2 = 900$

$b = \sqrt{900}$

$b = 30$

Your welcome and don't forget to say <u>Thanks</u>

7 0

3 years ago

What is the solution for x if x/8= -8

LuckyWell [14K]

Answer:

x=-1

Step-by-step explanation:

just like 8/8 is 1 the same concept only you add a negative

8 0

3 years ago

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How many pairs of consecutive natural numbers have a product of less than 40000? I am in 5th grade. This is supposed to be easy

Ugo [173]

Answer:

There are 199 pairs of consecutive natural numbers whose product is less than 40000.

Step-by-step explanation:

We notice that such statement can be translated into this inequation:

$n \cdot (n+1) < 40000$

Now we solve this inequation to the highest value of $n$ that satisfy the inequation:

$n^{2}+n < 40000$

$n^{2}+n -40000$

The Quadratic Formula shows that roots are:

$n_{1,2} = \frac{-1\pm\sqrt{1^{2}-4\cdot (1)\cdot (-40000)}}{2\cdot (1)}$

$n_{1,2} = -\frac{1}{2}\pm \frac{1}{2} \cdot \sqrt{160001}$

$n_{1} = -\frac{1}{2}+\frac{1}{2}\cdot \sqrt{160001}$

$n_{1} \approx 199.501$

$n_{2} = -\frac{1}{2}-\frac{1}{2}\cdot \sqrt{160001}$

$n_{2} \approx -200.501$

Only the first root is valid source to determine the highest possible value of $n$ , which is $n_{max} = 199$ . Each natural number represents an element itself and each pair represents an element as a function of the lowest consecutive natural number. Hence, there are 199 pairs of consecutive natural numbers whose product is less than 40000.

6 0

3 years ago