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Ludmilka [50]
3 years ago
11

. Find the value of $1,300 invested at 4.2% interest compounded continuously for 5 years, 9 months. Round your final answer to t

he nearest hundredth, or cent, and show your work. Use e=2.718
Mathematics
1 answer:
BARSIC [14]3 years ago
5 0
The formula we use for continuous compounding is A=Pe ^{rt} where P is the initial amount invested, r is the rate as a decimal, and t is time in years.  Our P = 1300, our r = .042, and our t = 5.75 (9 months is 3/4 of a year, and 3/4 in a decimal is .75).  Putting all that into our formula we have A=1300(2.718) ^{(.042)(5.75)}.  We have to multiply those 2 powers together and then raise euler's number to it, then multiply by 1300.  Doing all of that, we get the amount at the end to be $1,655.10
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3 years ago
If a formula of a triangle is 18 = (h - 1) x 6 x .5 how would you get your answer?
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The box plot shows the undergraduate in-state tuition per credit hour at four-year public colleges. 0 300 600 900 1,200 $1,500 a
kkurt [141]

Answer:

(a) The median estimate is 450.

(b) The first and third quartiles are 300 and 750 respectively.

(c) The interquartile range is 450.

(d) The particular value which is less than 150 or it is more than 1200, is considered as an outlier.

(e) Yes, there is one outlier in our data which is the value of 1,500.

(f) The distribution is positively skewed.

Step-by-step explanation:

We are given that the box plot shows the undergraduate in-state tuition per credit hour at four-year public colleges. 0, 300, 600, 900, 1,200, 1,500.

(a) As we can see in the box plot that the middlemost data lies between 300 and 600, that means;

Median is given by the average of the two numbers, i.e;

             Median =  \frac{300+600}{2}

                           =  \frac{900}{2}  = 450

So, the median estimate is 450.

(b) As we know that the first quartile represents 25% of the data values and the third quartile represents 75% of the data values.

So, from the box plot given; we can observe that the first quartile, Q_1 = 300 and the third quartile lies between the values of 600 and 900, i.e;

Third quartile, Q_3 = \frac{600+900}{2}

                             =  \frac{1500}{2}  = 750

So, the first and third quartiles are 300 and 750 respectively.

(c) The interquartile range is given by the following formula;

          Interquartile range = Third quartile - First quartile

                                          =  Q_3-Q_1

                                          =  750 - 300 = 450

(d) From the box plot; it is clear that if the particular value is less than 150 or it is more than 1200, then it is considered as an outlier.

(e) Yes, there is one outlier in our data which is the value of 1,500.

(f) The distribution is positively skewed because the more values are on the right side of the curve and it skewed towards the right.

4 0
4 years ago
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