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3 years ago

12

How are fractions related to decimals

2 answers:

masya89 [10]3 years ago

8 0

You can turn a decimal into a fraction or a fraction into a decimal

irina1246 [14]3 years ago

6 0

Fractions and decimals can be written as a percent

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Luis went to the bank he deposited $20 into his savings account and withdrew $40 from his checking account. Write integers to de

aliina [53]

Answer:

Savings Account: x+20

Checking Account:x-40

7 0

3 years ago

Talia attended a 555-day math camp that lasted \dfrac56

Vaselesa [24]

Complete Question

Talia attended a 5 -day math camp that lasted 5/6 of an hour each day. How many hours did Talia spend at the math camp?

Answer:

4 1/6 hours

Step-by-step explanation:

1 day = 5/6 hour

5 days = x

Cross Multiply

x = 5/6 × 5 days

x = 25/6 hours

x = 4 1/6 hours

Therefore, Talia spent 4 1/6 hours at camp.

6 0

2 years ago

The corners of a meadow are shown on a coordinate grid. Ethan wants to fence the meadow. What length of fencing is required?

Nuetrik [128]

Answer:

34.6 units

Step-by-step explanation:

The lenght of fencing required is the total distance between point A to B, B to C, C to D, and D to A. That is the distance between all 4 corners of the meadow.

The coordinates of the corners of the meadow is shown on a coordinate plane in the attachment. (See attachment below).

Let's use the distance formula to calculate the distance between the 4 corners of the meadow using their coordinates as follows:

Distance between point A(-6, 2) and point B(2, 6):

$AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$A(-6, 2)) = (x_1, y_1)$

$B(2, 6) = (x_2, y_2)$

$AB = \sqrt{(2 - (-6))^2 + (6 - 2)^2}$

$AB = \sqrt{(8)^2 + (4)^2}$

$AB = \sqrt{64 + 16} = \sqrt{80}$

$AB = 8.9$ (nearest tenth)

Distance between B(2, 6) and C(7, 1):

$BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$B(2, 6) = (x_1, y_1)$

$C(7, 1) = (x_2, y_2)$

$BC = \sqrt{(7 - 2)^2 + (1 - 6)^2}$

$BC = \sqrt{(5)^2 + (-5)^2}$

$BC = \sqrt{25 + 25} = \sqrt{50}$

$BC = 7.1$ (nearest tenth)

Distance between C(7, 1) and D(3, -5):

$CD = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$C(7, 1) = (x_1, y_1)$

$D(3, -5) = (x_2, y_2)$

$CD = \sqrt{(3 - 7)^2 + (-5 - 1)^2}$

$CD = \sqrt{(-4)^2 + (-6)^2}$

$CD = \sqrt{16 + 36} = \sqrt{52}$

$CD = 7.2$ (nearest tenth)

Distance between D(3, -5) and A(-6, 2):

$DA = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$D(3, -5) = (x_1, y_1)$

$A(-6, 2) = (x_2, y_2)$

$DA = \sqrt{(-6 - 3)^2 + (2 - (-5))^2}$

$DA = \sqrt{(-9)^2 + (7)^2}$

$DA = \sqrt{81 + 49} = \sqrt{130}$

$DA = 11.4$ (nearest tenth)

Length of fencing required = 8.9 + 7.1 + 7.2 + 11.4 = 34.6 units

8 0

2 years ago

1<br> _x = 9 <br> 6<br> Solving equations

Zina [86]

Hello friend,. I hope it's helps you

enjoy your day

4 0

3 years ago

I spent 3/4 of my money and then I spent 1/5 of what was left.

Alborosie

1/20 is the fraction that you'll have left

6 0

2 years ago