All categories

3 years ago

Find the volume of the following rectangular prism with dimensions of 9 yards by 7 yards by 5 yards

Mathematics

2 answers:

guapka [62]3 years ago

7 0

Answer:315

Step-by-step explanation: The formula for finding the volume of a rectangular prism is: LxWxH. So 9x7x5 = 315units^3

brilliants [131]3 years ago

5 0

Answer:

It would be 315 yards.

Step-by-step explanation:

You would find the volume by multiplying all of the given lengths.

9 x 7 x 5 = ?

Start off by multiplying two of the numbers.

7 x 5 = 35

Now, replace those two numbers with the product.

9 x 35 = ?

You can do this to solve with no difficulty. Now, you would multiply.

The answer would be 315.

You might be interested in

Geometry Question Help if you can please

docker41 [41]

Answer:

≈ 78.55 cm

Step-by-step explanation:

Using the ratio of arc (AB) to circumference (C) is equal to the ratio of angle subtended at centre by arc AB to 360°, that is

$\frac{AB}{C}$ = $\frac{110}{360}$ , that is

$\frac{24}{C}$ = $\frac{110}{360}$ ( cross- multiply )

110C = 8640 ( divide both sides by 110 )

C = $\frac{8640}{110}$ ≈ 78.55 cm ( to 2 dec. places )

5 0

3 years ago

Which of the following can you determine, when you use deduction and start

Tomtit [17]

Pretty sure the answer is c :))

4 0

3 years ago

Read 2 more answers

A five-sided solid has the numbers 1, 2, 3, 4, and 5. What is the probability of rolling two five-sided number solids and gettin

Umnica [9.8K]

The answer is 1 out of 5

4 0

3 years ago

Consider the system of quadratic equations \begin{align*} y &=3x^2 - 5x, \\ y &= 2x^2 - x - c, \end{align*}where $c$ is

shtirl [24]

Hello, we need to solve this system, c being a real number.

$\begin{cases}y &= 3x^2-5x\\y &= 2x^2-x-c\end{cases}$

y=y, right? So, it comes.

$3x^2-5x=2x^2-x-c\\\\3x^2-2x^2-5x+x+c=0\\\\\boxed{x^2-4x+c=0}$

We can compute the discriminant.

$\Delta=b^2-4ac=4^2-4c=4(4-c)$

If the discriminant is 0, there is 1 solution.

It means for $4(4-c)=0 4-c=0 \boxed{c=4}$

And the solution is

$x_2=x_1=\dfrac{4}{2}=2$

If the discriminant is > 0, there are 2 real solutions.

It means 4(4-c) > 0 <=> 4-c > 0 <=> $\boxed{c$

And the solution are

$x_1=\dfrac{4-\sqrt{4(4-c)}}{2}=\dfrac{4-2\sqrt{4-c}}{2}=2-\sqrt{4-c}\\\\x_2=2+\sqrt{4-c}$

If the discriminant is < 0, there are no real solutions.

It means 4(4-c) < 0 <=> 4-c < 0 <=> $\boxed{c>4}$

There are no real solutions and the complex solutions are

$x_1=\dfrac{4-\sqrt{4(4-c)}}{2}=\dfrac{4-2\sqrt{i^2(c-4)}}{2}=2-\sqrt{c-4}\cdot i\\\\x_2=2+\sqrt{c-4}\cdot i$

Thank you.

8 0

4 years ago

Given that . In the space below, type a function that would shift f(x) right 2.5 units, down 7 units, vertically shrink the func

Mkey [24]

Y = a |x-k|+h

a = slope it can be either vertical compression or vertical stretch
k = determines if a point should move right or left (x-axis)
h = determines if a point should move up or down (y-axis)

The answer to the question would be
y = - |x - 2.5|-7

4 0

4 years ago