Question

If (y) varies directly with x, and y=3 when x=0.2, what is the value of (y) when x=1?

Answer 1

As y varies directly with x, there is a proportionality constant. As x increases by that certain constant, y also increases. We equate:
y = kx
where k = proportionality constant.
Given the condition, y = 3 when x = 0.2, then we solve for k:
3 = k(0.2)
k = 3/0.2 = 15
When x = 1, then
y = 15(1) = 15 (ANSWER)

Answer 2

_Brainliest if helped!!

since it varies directly, we form an equation ,  
Y =kX  where k is a constant
use the points given to find K ,
3 =0.2k , k = 15

So to get final answer, 

when x = 1 
y  = kx, = 1(15)
y= 15

Hence when x=1,    < y = 15 >