Answer:
The graph approaches –3 as x approaches infinity. Option a is correct.
Step-by-step explanation:
The given function is

We have to find value of function as x approaches infinity. Take limit both sides as x approaches to infinity.

Taking x common from the denominator.

Cancel out common factor x.

Apply limits.



Therefore the graph approaches –3 as x approaches infinity.
Answer:
Which graph is the result of reflecting f(x) = One-fourth(8)x across the y-axis and then across the x-axis?
On a coordinate plane, an exponential function approaches y = 0 in quadrant 2 and incresaes into quadrant 1. It goes through the y-axis at (0, 0.25) and goes through (1, 2).
On a coordinate plane, an exponential function approaches y = 0 in quadrant 1 and increases in quadrant 2. It crosses the y-axis at (0, 0.25) and goes through (negative 1, 2).
On a coordinate plane, an exponential function approaches y = 0 in quadrant 3 and decreases into quadrant 4. It crosses the y-axis at (0, negative 0.25) and goes through (1, negative 2).
On a coordinate plane, an exponential funtion increases in quadrant 3 into quadrant 4 and approaches y = 0. It goes through (negative 1, negative 2) and crosses the y-axis at (0, negative 0.25).Step-by-step explanation:
Answer:
m = -5/2
Step-by-step explanation:
Solve for slope with the following equation:
<em>m </em>(slope) = (y₂ - y₁)/(x₂ - x₁)
Let:
(4 , -12) = (x₁ , y₁)
(-2 , 3) = (x₂ , y₂)
Plug in the corresponding numbers to the corresponding variables:
<em>m </em>= (3 - (-12))/(-2 - 4)
<em>m</em> = (3 + 12)/(-2 - 4)
<em>m </em>= (15)/(-6)
Simplify the slope:
<em>m</em> = -(15/6) = -5/2
-5/2 is your slope.
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Answer:
She can run 24 laps in 1 hour and 15 minutes.
Answer:
show me, I cant see anything