For 90% of users, the word processing capabilities of Google Docs is more than enough. But for some, Microsoft Word's advanced features will be important. ... You also get far more powerful templates, which could speed up your work, depending on what you use Word for.
We use analog and digital signals in our everyday lives with the radio, the cell phone and with our own computers. our computers and our cell phones are all digital now but radio's are still considered analog. Radio telescopes explore space by using radio waves and signals to almost like scan space and collect data like a sonar in a submarine.
Answer:
Explanation:
#include <iostream>
using namespace std;
int costdays(int);
int costhrs(int,int);
int main()
{
int dd,hh,mm,tmph,tmpd,tmpm=0;
int pcost,mcost=0;
cout<<"Enter Parking time" << endl;
cout<<"Hours: ";
cin>>hh;
cout<<"Minutes: ";
cin>>mm;
if (mm>60)
{
tmph=mm/60;
hh+=tmph;
mm-=(tmph*60);
}
if (hh>24)
{
tmpd=hh/24;
dd+=tmpd;
hh-=(tmpd*24);
}
if ((hh>4)&&(mm>0))
{
pcost+=costdays(1);
}
else
{
mcost=costhrs(hh,mm);
}
cout<<"Total time: ";
if (dd>0)
{
cout<<dd<<"days ";
pcost+=costdays(dd);
}
pcost+=mcost;
cout<<hh<<"h "<<mm<<"mins"<<endl;
cout<<"Total Cost :"<<pcost<<"Won";
return 0;
}
int costdays(int dd)
{
return(dd*25000);
}
int costhrs(int hh,int mm)
{
int tmpm, tmp=0;
tmp=(hh*6)*1000;
tmp+=(mm/10)*1000;
tmpm=mm-((mm/10)*10);
if (tmpm>0)
{
tmp+=1000;
}
return(tmp);
}
The best way of doing this would be when you are opening a document application, the first thing that you would do in this case in to click "new". And by clicking new, you would have a fresh new spread sheet.
Answer:
public static void removeInRange(List<Integer> list, int value, int start, int end) {
for (int i = end - 1; i >= start; i--) {
if (list.get(i) == value) {
list.remove(i);
}
}
System.out.println(list);
}
Explanation:
- Create a method named <em>removeInRange</em> that takes four parameters, a list, an integer number, a starting index and an ending index
- Inside the method, initialize a <u>for loop</u> that iterates between starting index and ending index
- If any number between these ranges is equal to the given <em>value</em>, then remove that value from the list, using <u>remove</u> method
- When the loop is done, print the new list
