Answer:
Python 2:
with open("datafile") as myfile:
head = [next(myfile) for x in xrange(N)]
print head
Python 3:
with open("datafile") as myfile:
head = [next(myfile) for x in range(N)]
print(head)
Both Python 2 & 3:
from itertools import islice
with open("datafile") as myfile:
head = list(islice(myfile, N))
print head
Answer:
The answer is "Option a"
Explanation:
In Microsoft Office, excel provides a field row, that is also known as an Information. in which a database, may be separated into a relational database. It also arranges the information and collects tables and, each record includes many fields. In this filed data is directly typed, that's why it is "true".
Answer:
public class Match
{
public static void main(String[] args) {
final int NUM_VALS = 4;
int[] userValues = new int[NUM_VALS];
int matchValue, numMatches = 0;
userValues[0] = 2;
userValues[1] = 2;
userValues[2] = 1;
userValues[3] = 2;
matchValue = 2;
for(int i = 0; i < NUM_VALS; ++i) {
if(userValues[i] == matchValue)
numMatches++;
}
System.out.println("Match Value: " + matchValue + ", Number of Matches: " + numMatches);
}
Explanation:
- Initialize the userValues array with length of NUM_VALS, which is initialized as 4
- Assign the numbers to the userValues array
- Update matchValue as 2
- Initialize a for loop that iterates through userValues array. If a number that is equal to matchValue found in array, increase the numMatches by 1
- Print the matchValue and numMatches
Answer:
MLA citations, in text and end-text, are commonly used by english students.
Answer:
The solution code is written in Java
- public static void checkCommonValues(int arr1[], int arr2[]){
- if(arr1.length < arr2.length){
- for(int i = 0; i < arr1.length; i++){
- for(int j = 0; j < arr2.length; j++){
- if(arr1[i] == arr2[j]){
- System.out.print(arr1[i] + " ");
- }
- }
- }
- }
- else{
- for(int i = 0; i < arr2.length; i++){
- for(int j = 0; j < arr1.length; j++){
- if(arr2[i] == arr1[j]){
- System.out.print(arr2[i] + " ");
- }
- }
- }
- }
- }
Explanation:
The key idea of this method is to repeated get a value from the shorter array to check against the all the values from a longer array. If any comparison result in True, the program shall display the integer.
Based on this idea, an if-else condition is defined (Line 2). Outer loop will traverse through the shorter array (Line 3, 12) and the inner loop will traverse the longer array (Line 4, 13). Within the inner loop, there is another if condition to check if the current value is equal to any value in the longer array, if so, print the common value (Line 5-7, 14-16).