All categories

2 years ago

Which of these numbers is between 5/6 and 1? (A) 4/5 (B) 4/7 (C)6/7

1 answer:

8 0

Two basic ways in which to do this problem:

1. Find and apply the LCD.

2. Convert all of the given numbers to their decimal form, to 2 or 3 places only.

Try #2 first:

5/6 = 0.83

4/5 = 0.80 is not between 5/6 and 1. Reject it.
4/7 = 0.57 Reject
6/7 = 0.86 This is between 5/6 and1. This is the answer.

You might be interested in

Question #1 Pls help

max2010maxim [7]

Answer:

C. Strong Positive Linear Relationship

Step-by-step explanation:

If you were to draw a line through the points all of the points would be near the line therefore it has a strong correlation

The points are going upwards from left to right which indicates that the relationship is positive

From this information we can make a conclusion

This scatter plot has a strong positive linear relationship

6 0

2 years ago

Find the Jacobian ∂(x, y, z) ∂(u, v, w) for the indicated change of variables. If x = f(u, v, w), y = g(u, v, w), and z = h(u, v

jeyben [28]

Answer:

The Jacobian ∂(x, y, z) ∂(u, v, w) for the indicated change of variables

= -3072uv

Step-by-step explanation:

Step :-(i)

Given x = 1 6 (u + v) …(i)

Differentiating equation (i) partially with respective to 'u'

$\frac{∂x}{∂u} = 16(1)+16(0)=16$

Differentiating equation (i) partially with respective to 'v'

$\frac{∂x}{∂v} = 16(0)+16(1)=16$

Differentiating equation (i) partially with respective to 'w'

$\frac{∂x}{∂w} = 0$

Given y = 1 6 (u − v) …(ii)

Differentiating equation (ii) partially with respective to 'u'

$\frac{∂y}{∂u} = 16(1) - 16(0)=16$

Differentiating equation (ii) partially with respective to 'v'

$\frac{∂y}{∂v} = 16(0) - 16(1)= - 16$

Differentiating equation (ii) partially with respective to 'w'

$\frac{∂y}{∂w} = 0$

Given z = 6uvw ..(iii)

Differentiating equation (iii) partially with respective to 'u'

$\frac{∂z}{∂u} = 6vw$

Differentiating equation (iii) partially with respective to 'v'

$\frac{∂z}{∂v} =6 u (1)w=6uw$

Differentiating equation (iii) partially with respective to 'w'

$\frac{∂z}{∂w} =6 uv(1)=6uv$

Step :-(ii)

The Jacobian ∂(x, y, z)/ ∂(u, v, w) =

$\left|\begin{array}{ccc}16&16&0\\16&-16&0\\6vw&6uw&6uv\end{array}\right|$

Determinant 16(-16×6uv-0)-16(16×6uv)+0(0) = - 1536uv-1536uv

= -3072uv

Final answer:-

The Jacobian ∂(x, y, z)/ ∂(u, v, w) = -3072uv

6 0

2 years ago

16 feet perimeter 5 feet long what is the width

miskamm [114]

P=2L+2W
L=Length
W=Width
P=Perimeter=16
So you have:
16=2×5+2w
Multiply 2 and 5 and get:
16=10+2w
Subtract 10 from both sides and get:
6=2w
Divide by 2 and get:
3=W
The width is 3.

8 0

2 years ago

What is the product of (7x+3)^2

Natali [406]

Answer:

49x² + 42x + 9

Step-by-step explanation:

Given

(7x + 3)²

= (7x + 3)(7x + 3)

Each term in the second factor is multiplied by each term in the first factor, that is

7x(7x + 3) + 3(7x + 3) ← distribute both parenthesis

= 49x² + 21x + 21x + 9 ← collect like terms

= 49x² + 42x + 9

7 0

2 years ago

Read 2 more answers

Suppose you are determining the growth rate of two species of plants. Species A ls 25 cm tall and grows 3 cm per month. Species

exis [7]

Answer: Last Option

$H (m) = 25 + 3m\\H (m) = 10 + 8m$

Step-by-step explanation:

The initial height of the plant of species A is 25 cm and grows 3 centimeters per month.

If m represents the number of months elapsed then the equation for the height of the plant of species A is:

$H (m) = 25 + 3m$

For species B the initial height is 10 cm and it grows 8 cm each month

If m represents the number of months elapsed then the equation for the height of the plant of species B is:

$H (m) = 10 + 8m$

Finally, the system of equations is:

$H (m) = 25 + 3m\\H (m) = 10 + 8m$

The answer is the last option

8 0

3 years ago