Given \qquad m \angle LONm∠LONm, angle, L, O, N is a straight angle. \qquad m \angle MON = 8x - 13^\circm∠MON=8x−13 ∘ m, angle,
M, O, N, equals, 8, x, minus, 13, degrees \qquad m \angle LOM = 7x - 17^\circm∠LOM=7x−17 ∘ m, angle, L, O, M, equals, 7, x, minus, 17, degrees Find m\angle MONm∠MONm, angle, M, O, N:
Let's convert the equation into slope-intercept form.
3x + 18y = 4 Subtract 3x from both sides. 18y= -3x + 4 Divide both sides by 18. y = -3/18x + 4/18 Simplify. y = -1/6x + 2/9
To make a line perpendicular, we need the slope to be the reciprocal of the other. Flip the denominator and numerator, and change the sign. We also have to change the b to make the line go through (-2, 1)
-1/6 to +6/1, or 6.
y = 6x + b
Input the x and y values and solve for b.
1 = 6(-2) + b 1 = -12 + b Add 12 to both sides. 13 = b