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stich3 [128]
3 years ago
10

If scott does 3 pushups everyday and starts at 2 on the first day how many does he do on day 30

Mathematics
1 answer:
Katarina [22]3 years ago
8 0

Answer:

89

Step-by-step explanation:

3 x 30 - 1 (because he did 2 instead of three)

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Here all the given equations are in the form of

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The value of x can be determined by the perfect square method as follows:

ax^2+bx+c=0

\Rightarrow x^2+\frac{b}{a}+\frac{c}{a}=0

\Rightarrow x^2+2\times\frac{b}{2a}+\left(\frac{b}{2a}\right)^2-\left(\frac{b}{2a}\right)^2+\frac{c}{a}=0

\Rightarrow \left(x+\frac{b}{2a}\right)^2=\left(\frac{b}{2a}\right)^2-\frac{c}{a}

\Rightarrow x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\;\cdots(i)

Now, for x^2+3x-4=0

a=1, b=3, c=-4

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x=\frac{-3\pm\sqrt{3^2-4\times1\times(-4)}}{2\times1}

\Rightarrow x=\frac{3\pm\sqrt{9+16}}{2}

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\Rightarrow x=\frac{3+5}{2},\frac{3-5}{2}

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Similarly, for 9x^2+12x+4=0

a=9, b=12, c=4

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x=\frac{-12\pm\sqrt{12^2-4\times9\times4}}{2\times9}

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\Rightarrow x=\frac{-2}{3}

For x^2-2x-3=0

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x=\frac{-(-2)\pm\sqrt{(-2)^2-4\times1\times(-3)}}{2\times1}

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a=1, b=-6, c=9

x=\frac{-(-6)\pm\sqrt{(-6)^2-4\times1\times9}}{2\times1}

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a=2, b=-4, c=-3

x=\frac{-(-4)\pm\sqrt{(-4)^2-4\times2\times(-3)}}{2\times2}

\Rightarrow x=\frac{4\pm\sqrt{40}}{4}

\Rightarrow x=\frac{4\pm2\sqrt{10}}{4}

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4 years ago
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vodomira [7]
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Step-by-step explanation:

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Answer:

2 is the answer

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