Answer:
 
 
Step-by-step explanation:
Let's use the definition of the Laplace transform and the identity given:![\mathcal{L}[t \cos 5t]=(-1)F'(s)](https://tex.z-dn.net/?f=%5Cmathcal%7BL%7D%5Bt%20%5Ccos%205t%5D%3D%28-1%29F%27%28s%29) with
 with ![F(s)=\mathcal{L}[\cos 5t]](https://tex.z-dn.net/?f=F%28s%29%3D%5Cmathcal%7BL%7D%5B%5Ccos%205t%5D) .
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Now,  . Using integration by parts with u=e^(-st) and dv=cos(5t), we obtain that
. Using integration by parts with u=e^(-st) and dv=cos(5t), we obtain that  .
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Using integration by parts again with u=e^(-st) and dv=sin(5t), we obtain that
  .
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Solving for F(s) on the last equation,  , then the Laplace transform we were searching is
, then the Laplace transform we were searching is  
 
 
        
             
        
        
        
Y= 2 (x^2-3x+2)
y= 2 (x-1) (x-2)
x=2 and x=1
        
                    
             
        
        
        
C is the answer 
for example 
assume that the height of a rectangular prism is 2, width is 1 and length measures 3 
the volume will be 6
(2*1*3) 
if we multiply height with the scale factor of 1/2
it becomes 1 
so the volume will be 3
(1*1*3)
this situation goes for other examples, too 
good luck
        
             
        
        
        
Answer:
Step-by-step explanation:

 
        
             
        
        
        
Answer:
asymptote
Step-by-step explanation: