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Mariulka [41]
3 years ago
7

What is the surface area of a square pyramid that has a base length of 5 inches and triangular faces that are 9 inches tall

Mathematics
1 answer:
scZoUnD [109]3 years ago
7 0

Answer:

115 in²

Step-by-step explanation:

SA = Area of triangular surfaces + area of the square base

SA= 2bh + b²

SA = 2(5)(9)+5²

SA = 90+25

SA = 115

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A packaging company is planning is in the planning stages of creating a box that include a three dimensional support inside the
Oliga [24]

Answer:

The length of the diagonal support is 69 feet.

Step-by-step explanation:

Dimensions of the box: length = 6 feet

                                       width = 5 feet

                                       height = 8 feet

The diagonal support relates with the diagonal of the base and the height.

From the base of the box, let the length of its diagonal be represented by x. Applying Pythagoras theorem;

/Hyp/^{2} = /Adj 1/^{2} + /Adj 2/^{2}

x^{2} = 6^{2} + 5^{2}

x^{2} = 36 + 25

   = 61

x = \sqrt{61}

  = 7.81

let the length of the diagonal support be represented by l. So that;

/Hyp/^{2} = /Adj 1/^{2} + /Adj 2/^{2}

l^{2} = x^{2} + 8^{2}

  = \sqrt{61} + 64

l  = \sqrt{\sqrt{61} + 64 }

  = 61 + 8

  = 69

Thus, the length of the diagonal support is 69 feet.

6 0
3 years ago
tammy is riding her bicycle. she rides for 27.5 kilometers at a speed of 11 kilometers per hr. how many hours does she ride?
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3 0
3 years ago
1<br> Solve:<br> -8–2k=-2(k+4)
Olegator [25]

Answer:

zero=0

Explanation:

-8-2k=-2(k+4)

-8-2k=-2k-8

-2k+2k=-8+8

zero=0

4 0
3 years ago
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