Answer:
1,3,5
Step-by-step explanation:
A=square root of 3 over 4 times a^2
<span>An example of a problem that has two parts, but that can be solved by finding the whole, might be the following:
Problem 1)
2/4+2/4=1 (whole number)
Problem 2)
2/3+1/3=1 (whole number)
</span>
<span>Ans : Note that:
sin(x) = sum(n=0 to infinity) [(-1)^n * x^(2n + 1)]/(2n + 1)!.
Then, since the series is alternating, the error in the approximation found by taking the first n terms of the series is no bigger than the n+1'th term. In other words:
E ≤ a_n+1 = x^(2n + 3)/(2n + 3)!.
(Note that a_n does not include (-1)^n, the alternating part)
We need that 1/6 ≤ x^(2n + 3)/(2n + 3)!. Given |x| < 1, n = 2 will be the least integer solution. Thus, we need 2 + 1 = 3 terms.</span>
Answer:
angle B=92
Step-by-step explanation:
cos C= adj/hyp
sin C=12/14=6/7 ( in rad.)
angle C is 31 degree
the sum of angles of triangle =180
angles A+B+C=180
angle B=180-(31+57)=92 degrees
