3 years ago

What is the surface area of a square pyramid that has a base length of 5 inches and triangular faces that are 9 inches tall

Mathematics

1 answer:

scZoUnD [109]3 years ago

7 0

Answer:

115 in²

Step-by-step explanation:

SA = Area of triangular surfaces + area of the square base

SA= 2bh + b²

SA = 2(5)(9)+5²

SA = 90+25

SA = 115

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3 years ago

How many terms are in the arithmetic sequence 9, 2, −5, . . . , −187?

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9, 2, -5... so is going down by 7 each time, meaning the "common difference" is -7.

$\bf n^{th}\textit{ term of an arithmetic sequence}\\\\
a_n=a_1+(n-1)d\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
d=\textit{common difference}\\
----------\\
a_1=9\\
d=-7\\
a_n=-187
\end{cases}
\\\\\\
-187=9+(n-1)(-7)\implies -187=9-7n+7
\\\\\\
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