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Brrunno [24]
3 years ago
13

A gardener is planting two types of trees:

Mathematics
1 answer:
Scrat [10]3 years ago
3 0

It will take 4 years for these trees to be the same height

Step-by-step explanation:

A gardener is planting two types of trees:

Type A is 6 feet tall and grows at a rate of 12 inches per year

Type B is 2 feet tall and grows at a rate of 24 inches per year

We need to find exactly how many years it will take for these trees to be the same height

Assume that it will take x years for these trees to be the same height

Type A:

∵ The initial height of the tree is 6 feet

∵ 1 foot = 12 inches

∴ 6 feet = 6 × 12 = 72 inches

∴ The initial height of the tree is 72 inches

∵ It grows at a rate of 12 inches per year

∵ The number of years is x

∴ The height of the tree in x years = 72 + 12 x

Type B:

∵ The initial height of the tree is 2 feet

∴ 2 feet = 2 × 12 = 24 inches

∴ The initial height of the tree is 24 inches

∵ It grows at a rate of 24 inches per year

∵ The number of years is x

∴ The height of the tree in x years = 24 + 24 x

Equate The heights of the two types

∴ 72 + 12 x = 24 + 24 x

- Subtract 2 from both sides

∴ 48 + 12 x = 24 x

- Subtract 12 x from both sides

∴ 48 = 12 x

- Divide both sides by 12

∴ x = 4

It will take 4 years for these trees to be the same height

Learn more:

You can learn more about the word problems in brainly.com/question/10557938

#LearnwithBrainly

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Please help me do to night
Vesna [10]

Answer:

1.) -4x+30y 2.) distributive property 3.) -4x+30y, (-0.4(3)+3(2)), 10(-1,2)+10(6), -12+60, =48

Step-by-step explanation:

10(-0.4x+3y)= 10(-0.4x)+10(3y)= -4x+30y

10(-0.4(3)+3(2))

10(-0.4(3))+10(3(2))

10(-1.2)+10(6)

-12+60

= 48

7 0
2 years ago
It is 3{:}32\text{ p.M.}3:32 p.M.3, colon, 32, start text, space, p, point, m, point, end text and Emma has gymnastics lessons a
Verizon [17]

Answer:

148 minutes

Step-by-step explanation:

It is 3{:}32\text{ p.M.}3:32 p.M.3, colon, 32, start text, space, p, point, m, point, end text and Emma has gymnastics lessons at 6{:}00\text{ p.M.}6:00 p.M.6, colon, 00, start text, space, p, point, m, point, end text How many minutes are there until Emma's gymnastics lessons?\

The time is 3:32 pm

Emma's gymnastics lesson is at 6:00 pm

6:00 pm - 3:32 pm = 2 hours 28 minutes

That is, we have 28 minutes before 4:00 pm

And 2 hours from 4:00 pm to 6:00 pm making a total of 2 hours 28 minutes

How many minutes are there until Emma's gymnastics lessons?

Convert 2 hours 28 minutes to minutes

1 hour = 60 minutes

2 hours = 60 minutes × 2 = 120 minutes

120 minutes + 28 minutes = 148 minutes

2 hours 28 minutes to minutes = 148 minutes

4 0
3 years ago
Solve the following system of equations by substitution. Show all steps.
Alinara [238K]

Answer:

Given system of equations:

\begin{cases}f(x)=-x^2+2x+3\\g(x)=-2x+3\end{cases}

To solve by substitution, equate the equations and solve for x:

\begin{aligned}f(x) & = g(x)\\\implies -x^2+2x+3 & = -2x+3\\-x^2+4x & = 0\\x^2-4x & = 0\\x(x-4) & = 0\\\implies x & = 0\\\implies x-4 & = 0 \implies x=4\end{aligned}

Therefore, the x-values of the solution are x = 0 and x = 4.

To find the y-values of the solution, substitute the found values of x into the functions:

f(0)=-(0)^2+2(0)+3=3

g(0)=-2(0)+3=3

f(4)=-(4)^2+2(4)+3=-5

g(4)=-2(4)+3=-5

Therefore, the solutions to the given system of equations are:

(0, 3) and (4, -5)

4 0
2 years ago
How is the series 5+11+17…+251 represented in summation notation?
NISA [10]

Answer:

\displaystyle \large{\sum_{n=1}^{42}(6n-1)

Step-by-step explanation:

Given:

  • Series 5+11+17+...+251

To find:

  • Summation notation of the given series

Summation Notation:

\displaystyle \large{\sum_{k=1}^n a_k}

Where n is the number of terms and \displaystyle \large{a_k} is general term.

First, determine what kind of series it is, there are two main series that everyone should know:

  • Arithmetic Series

A series that has common difference.

  • Geometric Series

A series that has common ratio.

If you notice and keep subtracting the next term with previous term:

  • 11-5 = 6
  • 17-11 = 6

Two common difference, we can in fact say that the series is arithmetic one. Since we know the type of series, we have to find the number of terms.

Now that brings us to arithmetic sequence, we know that first term is 5 and last term is 251, we’ll be finding both general term and number of term using arithmetic sequence:

<u>Arithmetic Sequence</u>

\displaystyle \large{a_n=a_1+(n-1)d}

Where \displaystyle \large{a_n} is the nth term, \displaystyle \large{a_1} is the first term and \displaystyle \large{d} is the common difference:

So for our general term:

\displaystyle \large{a_n=5+(n-1)6}\\\displaystyle \large{a_n=5+6n-6}\\\displaystyle \large{a_n=6n-1}

And for number of terms, substitute \displaystyle \large{a_n} = 251 and solve for n:

\displaystyle \large{251=6n-1}\\\displaystyle \large{252=6n}\\\displaystyle \large{n=42}

Now we can convert the series to summation notation as given the formula above, substitute as we get:

\displaystyle \large{\sum_{n=1}^{42}(6n-1)

5 0
2 years ago
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insens350 [35]

Answer:

Step-by-step explanation:

3\frac{3}{5ax_{3} }

5 0
3 years ago
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