Answer:
The base of the second parallelogram is 51cm.
Step-by-step explanation:
If the parallelograms are similar, it means by applying the same scale factor to all the sides in one gives you the other. The question tells us the height of the first shape is 8cm and the height of the second shape is 34cm. That means the scale factor is:
Apply this same scale factor to the base of the first shape to find the base of the second:
Answer:
Tan(b°) = 3/4 = three fourths (C)
Step-by-step explanation:
Triangle JKL is a right angled triangle in which angle K is a right angle and angle L= b°
We would apply SOHCAHTOA from trigonometry to determine the value for each sides.
For ∆JKL
Sin(b°) = opposite/hypotenuse
Sin(b°) = 3/5
Cos(b°) = adjacent/hypotenuse
Cos(b°) = 4/5
Tan(b°) = 3/4
From the above we know the value of each sides of ∆JKL
Find attached the diagram of the above triangle (1)
∆JKL is dilated by a scale factor = 2
Meaning we would multiply each sides of ∆JKL by 2. The values of the new triangle become:
Opposite = 2(3) = 6
Adjacent = 2(4) = 8
Hypotenuse = 2(5) = 10
To find tan(b°) of the new triangle, we would apply tangent ratio
Tan(b°) = opposite/adjacent
Tan(b°) = 6/8
Tan(b°) = 3/4
Find attached the diagram for the new triangle (2)
Diagram 3 shows the drawing of both triangles together.
From the above, we can see the angle doesn't change when a shape is dilated by a scale factor.
Therefore, tan(b°) = three fourths (C)
