Answer:
90° is correct answer. :)
You would use PEMDAS, which means Parenthesis, exponents, multiplication, division, addition" and then subtraction. You would solve the problem in that order
I believe it is D. Hope this helps!
Answer:
x ≈ 25.4 Km
Step-by-step explanation:
Using the tangent ratio in the right triangle on the right
tan54° = 
= 
( multiply both sides by 17 )
17 × tan54° = opp , thus
opp ≈ 23.4
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Using the cosine ratio in the right triangle on the left
cos23° = 
= 
( multiply both sides by x )
x × cos23° = 23.4 ( divide both sides by cos23° )
x = 
≈ 25. 4 Km ( to the nearest tenth )
Answer:
6.5 x 10^6 To answer this question, you need to divide the mass of the sun by the mass of mercury. So 2.13525 x 10^30 / 3.285 x 10^23 = ? To do the division, divide the mantissas in the normal fashion 2.13525 / 3.285 = 0.65 And subtract the exponents. 30 - 23 = 7 So you get 0.65 x 10^7 Unless the mantissa is zero, the mantissa must be greater than or equal to 0 and less than 10. So multiply the mantissa by 10 and then subtract 1 from the exponent, giving 6.5 x 10^6 So the sun is 6.5 x 10^6 times as massive as mercury.
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