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Damm [24]
4 years ago
15

Given j || k and m∠8=150° What is m∠3? Enter your answer in the box. m∠3= ___°

Mathematics
1 answer:
lions [1.4K]4 years ago
4 0

Answer:

30°

Step-by-step explanation:

•angle 8 would be the same as angle 6

•angle 6 is next to angle 3

•if you were to add angle 6 and 3 it should equal 180°

180-150=30°

i rlly hope this is correct and helps <3

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Do #11 I need help pleae
ryzh [129]
330 page/(3/4 Hour):==> 330 : 3/4
To solve this division you have to MULTIPLY the 1st term by the reciprocal of the 2nd (the reciprocal of 3/4 is 4/3), so

330 x 4/3 = (330x4)/3 = 440
330 pages were read in 3/4 Hour (given)  & in 1 hour. could be read

3 0
3 years ago
g Use this to find the equation of the tangent line to the parabola y = 2 x 2 − 7 x + 6 at the point ( 4 , 10 ) . The equation o
natali 33 [55]

Answer:

The tangent line to the given curve at the given point is y=9x-26.

Step-by-step explanation:

To find the slope of the tangent line we to compute the derivative of y=2x^2-7x+6 and then evaluate it for x=4.

(y=2x^2-7x+6)'          Differentiate the equation.

(y)'=(2x^2-7x+6)'       Differentiate both sides.

y'=(2x^2)'-(7x)'+(6)'    Sum/Difference rule applied: (f(x)\pmg(x))'=f'(x)\pm g'(x)

y'=2(x^2)'-7(x)'+(6)'  Constant multiple rule applied: (cf)'=c(f)'

y'2(2x)-7(1)+(6)'        Applied power rule: (x^n)'=nx^{n-1}

y'=4x-7+0               Simplifying and apply constant rule: (c)'=0

y'=4x-7                    Simplify.

Evaluate y' for x=4:

y'=4(4)-7

y'=16-7

y'=9 is the slope of the tangent line.

Point slope form of a line is:

y-y_1=m(x-x_1)

where m is the slope and (x_1,y_1) is a point on the line.

Insert 9 for m and (4,10) for (x_1,y_1):

y-10=9(x-4)

The intended form is y=mx+b which means we are going need to distribute and solve for y.

Distribute:

y-10=9x-36

Add 10 on both sides:

y=9x-26

The tangent line to the given curve at the given point is y=9x-26.

------------Formal Definition of Derivative----------------

The following limit will give us the derivative of the function f(x)=2x^2-7x+6 at x=4 (the slope of the tangent line at x=4):

\lim_{x \rightarrow 4}\frac{f(x)-f(4)}{x-4}

\lim_{x \rightarrow 4}\frac{2x^2-7x+6-10}{x-4}  We are given f(4)=10.

\lim_{x \rightarrow 4}\frac{2x^2-7x-4}{x-4}

Let's see if we can factor the top so we can cancel a pair of common factors from top and bottom to get rid of the x-4 on bottom:

2x^2-7x-4=(x-4)(2x+1)

Let's check this with FOIL:

First: x(2x)=2x^2

Outer: x(1)=x

Inner: (-4)(2x)=-8x

Last: -4(1)=-4

---------------------------------Add!

2x^2-7x-4

So the numerator and the denominator do contain a common factor.

This means we have this so far in the simplifying of the above limit:

\lim_{x \rightarrow 4}\frac{2x^2-7x-4}{x-4}

\lim_{x \rightarrow 4}\frac{(x-4)(2x+1)}{x-4}

\lim_{x \rightarrow 4}(2x+1)

Now we get to replace x with 4 since we have no division by 0 to worry about:

2(4)+1=8+1=9.

6 0
4 years ago
a salesperson earns $25 per day plus $2.50 for every sale. He normally earns $100 per day. How many sales does he normally get.
Dahasolnce [82]
He makes about 30 sales because he makes $100 typically but always makes a minimum of $25 making $75 worth of his sales. If you multiply 30 and $2.50 you get $75 in sales. His $25 minimum and $75 in sales make $100. So he makes 30 sales.
3 0
3 years ago
7c-11=17 what does c equal. Plz show work. Thanks :D
Gnom [1K]
Since you are subtracting 11 on the side with the variable, you have to add it on the other side. 17+11=28. Then, to solve the problem you are left with, 7c=28. You are multiplying on the side of the variable, so you divide 28 by 7. Your answer to the problem is C=4 i hope this helps
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3 years ago
In a math class there are 8 male students and 7 female students. A
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The answer is 2/15 I think
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