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WARRIOR [948]
3 years ago
14

I'm doing geometry. Does anyone know how to do this?

Mathematics
1 answer:
Deffense [45]3 years ago
3 0
You multiply the difference individual shapes then add all the shapes up to make it 3D
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Is it possible to name more than 5 decimal numbers between 4.78 and 4.79?
sleet_krkn [62]

It is possible to list more than 5 decimal numbers between 4.78 and 4.79.

The list is:

4.781

4.782

4.783

4.784

4.785

4.786

4.787

4.788

4.789

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4 years ago
What is the slope of the line for 3x+ 4y = 20?
Aneli [31]
Slope is -3/4
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Question 1 (1 point)
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I will do it and send it to you in 12 hours
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3 years ago
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Solve the system of equations and choose the correct ordered pair.
KiRa [710]
<span>4x + 3y = 16
7x + 6y = 31

Note what happens if we mult. the first eqn. by -2:  

-8x - 6y = -32

Combining this with the 2nd equation eliminates the variable y:

</span>-8x - 6y = -32<span>
7x + 6y = 31
--------------------
-x          = -1, or x = 1.  Sub 1 for x in either of the 2 given eqns to find y:

For example:  4(1) + 3y = 16, so 36 = 12, and y = 3.  Sol'n is (1,3).</span>
8 0
3 years ago
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n engineer designed a valve that will regulate water pressure on an automobile engine. The engineer designed the valve such that
BartSMP [9]

Answer:

<em>The calculated t- value =  1.11 > 2.89 at 0.025 level of significance</em>

<em>Null hypothesis is rejected </em>

<em>The engineer designed the valve such that it would produce a mean pressure is not equal to  5.4</em>

Step-by-step explanation:

<u><em>Step(i):-</em></u>

<em>Given mean of the Population (μ) = 5.4</em>

<em>Given sample size 'n' = 9</em>

<em>Mean of the sample (x⁻) = 5.7</em>

<em>Standard deviation of the sample (s) = 0.81</em>

<u><em>Step(ii):-</em></u>

<em>Null Hypothesis: H₀:</em>  The engineer designed the valve such that it would produce a mean pressure of 5.4

H₀: μ = 5.4

<em>Alternative Hypothesis : H₁:</em>  μ ≠ 5.4

Level of significance = 0.025

Test statistic

            t = \frac{x^{-} -mean}{\frac{S}{\sqrt{n} } }

           t = \frac{5.7 -5.4}{\frac{0.81}{\sqrt{9} } }

         t = 1.11

<em>Degrees of freedom </em>

<em>ν = n-1 = 9-1 =8</em>

t₀.₀₁₅ , ₈  = 2.89

<em>The calculated t- value =  1.11 > 2.89 at 0.025 level of significance</em>

<em>Null hypothesis is rejected </em>

<em>The engineer designed the valve such that it would produce a mean pressure is not equal to  5.4</em>

<em></em>

<em />

7 0
3 years ago
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