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yaroslaw [1]
3 years ago
8

Which of the following is true of utility patents? Select one:

Computers and Technology
1 answer:
Triss [41]3 years ago
4 0
<span>Utility Patents are used to patent machines and process and it is called patents for inventions. </span>
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Which website is important for hacking
Yuliya22 [10]

Answer:

Here's a few

Explanation:

  • SQL Injection attacks. SQL Injection attack is the most common website hacking technique. ...
  • Cross Site Scripting (XSS) ...
  • Denial of Service (DoS/DDoS) ...
  • Cross-site request forgery (CSRF or XSRF) ...
  • DNS Spoofing (DNS cache poisoning) ...
  • Social engineering techniques.

Glad I could help!!

6 0
3 years ago
A power ratio of 9000000:1 corresponds to ... dB?
sertanlavr [38]

Answer:

69.54

Explanation:

A power ratio of 9000000:1 corresponds to 69.54 dB.

The calculation is presented below:

Formula for calculating Power ratio (db) = 10 * log [P(out)/P(in)]

Since the given ratio is 9000000:1, substituting in the formula gives us 10 * log (9000000/1)

Note that log 9000000 = 6.954

Therefore, 10 * log (9000000/1) = 69.54

Hence the required power ratio in db is 69.54 db.

4 0
3 years ago
Company Wizzy is having trouble with network security. Issues with authentication, viruses, malware/spyware, and other network i
Darya [45]

Answer:

B) security as a service I'm just doing the work

4 0
3 years ago
I WILL UPVOTE!!!!!!!!!!!!!!!!!!
BabaBlast [244]
All of the answers above are correct
5 0
3 years ago
You are given an unsorted array x of elements that implement the Comparable interface. There are no duplicates in this array. Yo
Andrei [34K]

Answer:

boolean isEven = false;

if (x.length % 2 == 0)

isEven = true;

Comparable currentMax;

int currentMaxIndex;

for (int i = x.length - 1; i >= 1; i--)

{

currentMax = x[i];

currentMaxIndex = i;

for (int j = i - 1; j >= 0; j--)

{

if (((Comparable)currentMax).compareTo(x[j]) < 0)

{

currentMax = x[j];

currentMaxIndex = j;

}

}

x[currentMaxIndex] = x[i];

x[i] = currentMax;

}

Comparable a = null;

Comparable b = null;

if (isEven == true)

{

a = x[x.length/2];

b = x[(x.length/2) - 1];

if ((a).compareTo(b) > 0)

m = a;

else

m = b;

}

else

m = x[x.length/2];

8 0
4 years ago
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