<span>Saving at a young age could be a really great investment on your future from years from now. It has several benefits like learning how to handle your money properly, investing to grow your money more and an early retirement with a lot of coins in your pocket for when you want to enjoy traveling more.</span>
If I had an array of the names of people who just walked in the door. I’d append the name of the person who came in next. To update the array.
The append method needs to be looped through to add multiple inputs
Answer:
Size
Explanation:
Connectivity, they need internet to work.
Speed, they need it to work fast.
Storage, they need space to work.
Size, isn't all that important, unlike the rest.
Answer:
4) 3 11 44
Explanation:
Given data
int [] val = { 3, 10, 44 };
The total number of parameters of given array are 3, so total length of array is also 3.
The indexing of array starts with '0', Therefore the indexes of array with length zero are: {0,1,2}
The value of array at index 0 is = 3
similarly,
value at index 1 = 10
value at index 2 = 44
Here, Int i = 1 is storing the value '1' in integer variable i.
In addition to that, any value of index 'i' of an array is selected using array[i].
Therefore,
val[i] is selecting the value of array located at index '1' because i = 1.
val[i] = val[1] = 10
val[i]+1 is selecting the value of array located at index 'i' that is (1) and adding 1 to it
=> val[i] = 10
=> val[i]+1 = 10+1 = 11
Finally,
val[i] = val[i]+1; is copying the val[i]+1 = 11 to value placed at index 1 (10). Hence, the output would be {3 11 44}. So 4th option is correct.
Answer:
volume mount points
Explanation:
The best thing to do would be to use volume mount points. This is a feature that allows you to mount/target (from a single partition) another folder or storage disk that is connected to the system. This will easily allow the user in this scenario to access the different files located in the D: and E: drive from the C:\ drive itself. Without having to go and find each file in their own separate physical drive on the computer.
