Can someone tell me what operation to do
2 answers:
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Answer:
y = cot(x - ⅓π) + 2
Step-by-step explanation:
The general equation for a cotangent function with the given properties is
y = Acot(Bx + C) + D, where
A = the stretching factor
π/|B| = the period
C = the phase shift (negative is to the right)
D = the vertical shift
A = 1
π/|B| = π, so1/|B| = 1 and B = 1
C = -⅓π
D = 2
The function is
y = cot(x - ⅓π) + 2
The figure below shows the graph of the function with the given parameters.
Note that the parent function y = cot(x) has the y-axis as an asymptote, so we can measure the phase shift by the movement of the asymptote π units to the right.
Using the binomial distribution, it is found that there is a 0.0555 = 5.55% probability that more than 3 of these selected children have three siblings.
<h3>What is the binomial distribution formula?</h3>The formula is:
The parameters are:
- x is the number of successes.
- n is the number of trials.
- p is the probability of a success on a single trial.
In this problem, for the parameters, we consider that:
- 10% of the 9-year old children in a town have three siblings, hence p = 0.1.
- Fifteen 9-year old children are selected at random, hence n = 15.
The probability that more than 3 of these selected children have three siblings is given by:
In which:
Then:
P(X > 3) = 1 - 0.9445 = 0.0555
0.0555 = 5.55% probability that more than 3 of these selected children have three siblings.
More can be learned about the binomial distribution at brainly.com/question/24863377