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-BARSIC- [3]
3 years ago
13

Use rounding or compatible numbers to estimate sum of 87 +34

Mathematics
2 answers:
beks73 [17]3 years ago
8 0
If u round 87 its 90 and when you round 34 it is 30 then you add 90 and 30 and you get 120...
i hope this helped....
:) .........:)
TiliK225 [7]3 years ago
7 0
87 rounded is 90 and 34 rounded is 30 so 90+30=120
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Step-by-step explanation:

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Which expression is equivalent to (–3y – x) – (5y – 8x)? –8y – 8x –8y 7x 2y – 7x 8y 8x.
IRINA_888 [86]

The expression is equivalent to -8y + 7x.

Given

Expression; (-3y - x) - (5y - 8x)

<h3>How to find the equivalent expression?</h3>

To find the equivalent expression multiply the expression and add and simplify.

Then,

The expression is equivalent to;

 (-3y - x) - (5y - 8x)

-3y - x - 5y + 8x

-8y + 7x

Hence, the expression is equivalent to -8y + 7x.

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brainly.com/question/13040575

6 0
2 years ago
Let the random variable X be the number of rooms in a randomly chosen owner-occupied housing unit in a certain city. The distrib
natali 33 [55]

Answer:

a) X is a discrete random variable.

b) 2% probability of choosing a unit with 10 rooms

c) 98% probability that a unit chosen at random is not a 10-room unit

d) 30% probability that a unit chosen at random has less than five rooms

e) 7% probability that a unit chosen at random has less than five rooms

Step-by-step explanation:

The distribution means that:

7% probability that a randomly chosen owner-occupied housing unit in a certain city has 3 rooms.

23% probability that a randomly chosen owner-occupied housing unit in a certain city has 4 rooms.

36% probability that a randomly chosen owner-occupied housing unit in a certain city has 5 rooms.

19% probability that a randomly chosen owner-occupied housing unit in a certain city has 6 rooms.

5% probability that a randomly chosen owner-occupied housing unit in a certain city has 7 rooms.

5% probability that a randomly chosen owner-occupied housing unit in a certain city has 8 rooms.

3% probability that a randomly chosen owner-occupied housing unit in a certain city has 9 rooms.

?% probability that a randomly chosen owner-occupied housing unit in a certain city has 10 rooms.

(a) Is X a discrete or continuous random variable?

X is the number of rooms in a randomly selected house. The number of rooms is a countable variable, that is, only assumes values like 1,2,3,4,... You cannot have 3.5 rooms, for example.

So X is a discrete random variable.

(b) What must be the probability of choosing a unit with 10 rooms?

The sum of all probabilities must be 100%(1 decimal). So

0.07 + 0.23 + 0.36 + 0.19 + 0.05 + 0.05 + 0.03 + ? = 1

0.98 + ? = 1

? = 0.02

2% probability of choosing a unit with 10 rooms

(c) What is the probability that a unit chosen at random is not a 10-room unit?

0.07 + 0.23 + 0.36 + 0.19 + 0.05 + 0.05 + 0.03 = 0.98

98% probability that a unit chosen at random is not a 10-room unit

(d) What is the probability that a unit chosen at random has less than five rooms?

7% probability it has 3 rooms

23% probability it has 4 rooms. So

7+23 = 30% probability that a unit chosen at random has less than five rooms

(e) What is the probability that a unit chosen at random has three rooms?

7% probability that a randomly chosen owner-occupied housing unit in a certain city has 3 rooms. So

7% probability that a unit chosen at random has less than five rooms

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3 years ago
Find the value of each variable please
Sonbull [250]

Answer:

error

Step-by-step explanation:

7 0
3 years ago
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