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Westkost [7]
3 years ago
11

Two mechanics, Martin and Gordon, are working on your car. Martin can complete the work in 4 hours, while Gordon can complete th

e work in 2 hours. How many hours does the maintenance take if they work together?
Mathematics
1 answer:
ki77a [65]3 years ago
5 0

Answer: 4/3 hours or 1 1/3 hours

Step-by-step explanation:

From the question, we are told that two mechanics, Martin and Gordon, are working on your car. Martin can complete the work in 4 hours, while Gordon can complete the work in 2 hours.

Since Martin can complete the work in 4 hours, that means in 1 hour, he will do 1/4 of the work.

Since Gordon can complete the work in 2 hours, that means in 1 hour, he'll do 1/2 of the job.

When they both work together, we will add their fraction of work done in one hour together. This will be:

= 1/4 + 1/2

= 3/4

This means that both of them will do 3/4 of the job in one hour. Then to get the time taken to get the whole job done, we divide 1 by 3/4. This will be:

= 1 ÷ 3/4

= 1 × 4/3

= 4/3 hours

= 1 hour 20 minutes.

In one

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A large fish tank at an aquarium needs to be emptied so that it can be cleaned. When its
VikaD [51]

Answer:

The draining time when only the big drain is opened is 2.303 hours.

The draining time when only the small drain is opened is 5.303 hours.

Step-by-step explanation:

From Physics, we know that volume flow rate (\dot V), measured in liters per hour, is directly proportional to draining time (t), measured in hours. That is:

\dot V \propto \frac{1}{t}

\dot V = \frac{k}{t} (Eq. 1)

Where k is the proportionality constant, measured in liters.

From statement, we have the following three expressions:

(i) <em>Large and small drains are opened</em>

\dot V_{s}+\dot V_{l} = \frac{k}{2} (Eq. 2)

\frac{\dot V_{s}+\dot V_{l}}{k} = \frac{1}{2}

(ii) <em>Only the small drain is opened</em>

\dot V_{s} = \frac{k}{t_{l}+3} (Eq. 3)

\frac{\dot V_{s}}{k} = \frac{1}{t_{l}+3}

(iii) <em>Only the big drain is opened</em>

\dot V_{l} = \frac{k}{t_{l}} (Eq. 4)

\frac{\dot V_{l}}{k}  = \frac{1}{t_{l}}

By applying (Eqs. 3, 4) in (Eq. 2) and making some algebraic handling, we find that:

\frac{1}{t_{l}+3}+\frac{1}{t_{l}} = \frac{1}{2}

\frac{t_{l}+t_{l}+3}{t_{l}\cdot (t_{l}+3)} = \frac{1}{2}

2\cdot t_{l}+3 = t_{l}^{2}+3\cdot t_{l}

t_{l}^{2}-t_{l}-3 = 0 (Eq. 5)

Whose roots are determined by the Quadratic Formula:

t_{l,1}\approx 2.303\,h and t_{l,2} \approx -1.302\,h

Only the first roots offers a solution that is physically reasonable. Hence, the draining time when only the big drain is opened is 2.303 hours. And the time needed for the small drain is calculated by the following formula:

t_{s} = 2.303\,h+3\,h

t_{s} = 5.303\,h

The draining time when only the small drain is opened is 5.303 hours.

7 0
3 years ago
Use the figure below to identify angles and segment lengths
slega [8]

So Angle GEN and FED are vertical angles, which means that their angles are congruent. Therefore, Angle FED is 60°

Angle GEN and DEN are a linear pair, which means that they are supplementary angles (add up to 180). To find Angle DEN, we have to form the equation: 60 + DEN = 180

For this, all you have to do is subtract 60 on both sides, and your answer will be: DEN = 120°

6 0
3 years ago
Read 2 more answers
What is the first quartile (Q1) of the data set?
KATRIN_1 [288]
Sequence = 40, 45, 48, 51, 59, 62, 69, 74

Median = 51+59 / 2 = 55
First quartile = 40, 45, 48, 51 
So, it would be: 45 + 48 / 2 = 46.5

In short, Your Answer would be Option C

Hope this helps!
8 0
3 years ago
Which table most accurately organizes the data from the graph?
Brilliant_brown [7]

Answer

It's B

Step-by-step explanation:

It organizes the years from 1-6 and keeps the money consistent with the years

5 0
2 years ago
Can someone just help me with number 1 and 2
natta225 [31]

Answer:

dummy

Step-by-step explanation:

you are stupid

8 0
3 years ago
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