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3 years ago

10

I give a medal if you can figure this out fast! A certain forest covers an area of 4200 km2 . Suppose that each year this area d

ecreases by 8.5% . What will the area be after 8 years?

2 answers:

Mars2501 [29]3 years ago

8 0

The answer would be 525 kilometers2

oee [108]3 years ago

7 0

<span>1541.213 square km would be correct

</span>

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Each day, there is a 75% chance that elise will do her homework. what is the probability she does her homework on monday or tues

serg [7]

This problem is easier solved by finding the probability that she does NOT do her homework both Monday and Tuesday, which is obtained by the multiplication rule.

P(no HW on Monday) = 1-0.75 = 0.25
P(no HW on Tuesday) = 1-0.75 = 0.25
P(no HW on both Monday and Tuesday) = 0.25*0.25=0.0625
[by the multiplication rule]

This means that the rest of the time (1-0.0625=0.9375) Elsie does her homework either Monday, or Tuesday, or both days.
=>
P(HW either Monday, Tuesday, or both) = 0.9375

(note: in current English, Monday or Tuesday means "either Monday, Tuesday, or both days")

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3 years ago

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What is the inverse of the function <br><img src="https://tex.z-dn.net/?f=f%28x%29%20%3D%20%20%5Cfrac%7Bx%20%2B%201%7D%7Bx%7D%20

expeople1 [14]

Y=(x+1)/x

x=y+1 / y

x=1/(y-1)

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3 years ago

In a random sample of 45 newborn babies, what is the probability that 40% or fewer of the sample are boys. (Use 3 decimal places

erastova [34]

Answer:

$z= \frac{p- \mu_p}{\sigma_p}$

And the z score for 0.4 is

$z = \frac{0.4-0.4}{\sigma_p} = 0$

And then the probability desired would be:

$P(p$

Step-by-step explanation:

The normal approximation for this case is satisfied since the value for p is near to 0.5 and the sample size is large enough, and we have:

$np = 45*0.4= 18 >10$

$n(1-p) = 45*0.6= 27 >10$

For this case we can assume that the population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Where:

$\mu_{p}= \hat p = 0.4$

$\sigma_p = \sqrt{\frac{p(1-p)}(n} =\sqrt{\frac{0.4(1-0.4)}(45}= 0.0703$

And we want to find this probability:

$P(p$

And we can use the z score formula given by:

$z= \frac{p- \mu_p}{\sigma_p}$

And the z score for 0.4 is

$z = \frac{0.4-0.4}{\sigma_p} = 0$

And then the probability desired would be:

$P(p$

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3 years ago

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What is the height of an isosceles trapezoid, if the lengths of its bases are 5m and 11m, and the length of a leg 4m

son4ous [18]

In the isosceles trapezoid ABCD, draw two perpendiculars AM and BL from A and B to the side CD.

Now, LM = BA = 5 m

CD = CL + LM + MD

= CL + 5 + CL (CL = MD)

= 2CL + 5

But, CD = 11

Therefore, 2CL + 5 = 11

2CL = 11 - 5

= 6

CL = 6/2 = 3m

MD = 3m

Now, consider the right triangle AMD.

We have,

$AM^{2} = AD^{2} - MD^{2}$

= $4^{2} - 3^{2}$

= 16 - 9

= 7

Hence, height of the isosceles trapezoid = AM = $\sqrt{7} m$

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2 years ago

Plese help<br> plese<br> plese

Naya [18.7K]

B 25% percent because 15/60 is 25

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3 years ago

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