Answer:
15000
Step-by-step explanation:
Given that a professor wants to know how undergraduate students at X University feel about food services on campus, in general. She obtains a list of email addresses of all 15,000 registered undergraduates from the registrar’s office and mails a questionnaire to 300 students selected at random.
Only 150 questionnaires are returned.
So the sample size changed to 150. But population is the number of registered undergraduates which do not change.
Population size = 15000
Answer:
23 times 22 equals 506 but 23 times nothing can equal 500 thats what i think hope it helps in someway ig idk
Step-by-step explanation:
Answer:
the mean is the sum of them all divided by the number of terms.
mean: 13
the mode is the element that occurs MOST in the data set.
mode: none
the median is the middle value of all of the numbers.
median: 9
Hey there! I'm happy to help!
VOTES FOR MUNOZ TO SMITH
32:24
We see that both have a common factor of 8, so we can divide both by that.
4:3
This is in simplest form.
VOTES FOR PARK TO MUNOZ
20:32
We see that both have a common factor of 4, so we divide both by that.
5:8
This is completely simplified.
VOTES FOR SMITH TO TOTAL VOTES
24+32+20=76
24:76
We see that both have a common factor of 4, so will divide both by that.
6:19
We cannot simplify any more here.
VOTES FOR SMITH TO MUNOZ TO PARK
24:32:20
We can divide these all by four, so let's do that.
6:8:5
This can't be simplified anymore, so it is in simplest form.
Have a wonderful day! :D
Answer:
Step-by-step explanation:
The position of an object moving horizontally after t seconds is given by the function
s = 3t - t³
a) The object is stationary when there is no external force acting on the body. When the body is at rest, the body remains in a position and here is no distance covered by the object i.e s = 0
b) velocity is the change in displacement of a body with respect to time.
v = ds/dt
S = 3t - t³
V = ds/dt = 3-3t²
at t = 2
Velocity = 3-3(2)²
Velocity = 3-12
Velocity = -9m/s
c) acceleration is the change in velocity of a body with respect to time.
acceleration = dv/dt
If v = 3-3t²
a = dv/dt = -6t
When v = 0
0 = 3-3t²
-3 = -3t²
t² = 1
t = ±√1
t = 1sec
The acceleration of the object at v = 0 occurs at t = 1sec and -1sec
a = -6(1)
a = -6m/s²
d) Given the speed of the body v modelled by the function
v = 3-3t²
The speed is decreasing when it is less than zero as shown:
3-3t²< 0
3<3t²
1<t²
±1<t
1<t and -1<t
t>±1
t >1 and t>-1
The speed is decreasing when
3-3t²<0 and t>1 or t>-1
