So let's take a peek at both's ages, keep in mind, every year, is 1year added to Irene and 1year added to Fred
so... if we look at their ages

notice, Fred is always 40years older than Irene
thus, whatever age Irene is, let's say "i", then Fred is " i + 40 "
now, when is Fred 5 times Irene's age or 5*i or 5i? well,
f = fred's age i = irene's age
f = i + 40
now if f = 5i
5i = i + 40 <--- solve for "i" to see how old Irene was then
Answer:to Let f(t) = 6, g(t) = −5t, and h(t) = 2t2
Step-by-step explanation:
For this question you can say:
154/11 = 252/?
so ? is the hours she would work:
252*11/154 = 18 hours :)))
i hope this is helpful
have a nice day
it's 0.4 while it may look like 4% it's actually 40% of 1
When you don't know the answer on a multiple-choice questions it is generally best to guess a random answer instead of leaving it blank.
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