Dimensions of the rectangle (width and length) are 19 cm and 31 cm respectively.
Step-by-step explanation:
- Step 1: Given that the perimeter = 100 cm, let width be x cm and then length = 12 + x.
Perimeter of a rectangle = 2(length + width)
100 = 2(x + 12 + x)
100 = 4x + 24
4x = 100 - 24 = 76
∴ x = 76/4 = 19 cm
∴ Length = 19 + 12 = 31 cm
Answer:
the answer would be -13n-23
Step-by-step explanation:
first you want to distribute the brackets
-7(2+n) = -14-7n
+(-9-6n)
-9-6n
-14-7n-9-6n
combine the n value with an n value and an integer that doesn't have an n value
-7n-6n-14-9
= -13n-23
Answer:
22.29% probability that both of them scored above a 1520
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

The first step to solve the question is find the probability that a student has of scoring above 1520, which is 1 subtracted by the pvalue of Z when X = 1520.
So



has a pvalue of 0.5279
1 - 0.5279 = 0.4721
Each students has a 0.4721 probability of scoring above 1520.
What is the probability that both of them scored above a 1520?
Each students has a 0.4721 probability of scoring above 1520. So

22.29% probability that both of them scored above a 1520
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