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3 years ago

13

Please help answer correctly !!!!!!!!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!!!!!!!

1 answer:

pentagon [3]3 years ago

8 0

Answer:

DH is perpendicular to HG

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Please help! I think I have the equation set up.

ExtremeBDS [4]

$\bold{\huge{\underline{ Solution }}}$

<h3><u>Given :-</u></h3>

Here, we have given one quadrilateral that is quadrilateral ABCD
We also have given the angles of quadrilateral that is ( 6x + 5)° , ( 9x - 10)° , 80° and a right angle

<h3><u>To </u><u>Find </u><u>:</u><u>-</u></h3>

Here, we have to find the value of x

<h3><u>Let's </u><u>Begin </u><u>:</u><u>-</u><u> </u></h3>

We have given quadrilateral ABCD here , whose angles are as follows

Angle A = ( 6x + 5)°
Angle B = ( 9x - 10)°
Angle C = 80°
Angle D = A right angled triangle

[ The measure of right angled triangle is 90° ]

<u>We </u><u>know </u><u>that</u><u>, </u>

Sum of the angles of quadrilateral is equal to 360°

<u>That </u><u>is </u>

$\bold{\angle{ A + }}{\bold{\angle{B +}}}{\bold{\angle{C + }}}{\bold{\angle{D + = 360{\degree}}}}$

<u>Subsitute </u><u>the </u><u>required </u><u>values </u>

$\sf{ ( 6x + 5){\degree} + 80{\degree}+ 90{\degree} + (9x - 10){\degree} = 360{\degree}}$

$\sf{ 6x + 5 + 170{\degree} + 9x - 10 = 360{\degree}}$

$\sf{ 15x - 5 = 360{\degree} - 170{\degree}}$

$\sf{ 15x - 5 = 190 {\degree}}$

$\sf{ 15x = 190 {\degree} + 5 }$

$\sf{ 15x = 195 {\degree}}$

$\sf{ x = }{\sf{\dfrac{ 195}{15}}}$

$\sf{ x = }{\sf{\cancel{\dfrac{ 195}{15}}}}$

$\bold{ x = 13 }$

Hence, The value of x is 13 .

$\bold{\huge{\underline{\red{ Verification }}}}$

Measure of Angle A

$\sf{ = (6x + 5){\degree}}$

$\sf{ = (6(13) + 5 ){\degree}}$

$\sf{ = (78 + 5 ){\degree}}$

$\sf{ = 83{\degree}}$

Measure of Angle D

$\sf{ = (9x - 10){\degree}}$

$\sf{ = (9(13) - 10){\degree}}$

$\sf{ = (117 - 10 ){\degree}}$

$\sf{ = 107{\degree}}$

<u>Now</u><u>, </u><u> </u><u>we </u><u>know </u><u>that</u><u>, </u>

Sum of angles of triangles is equal to 360°

<u>That </u><u>is</u><u>, </u>

$\sf{ 83{\degree} + 80{\degree}+ 90{\degree} + 107 {\degree} = 360{\degree}}$

$\sf{ 163{\degree}+ 90{\degree} + 107 {\degree} = 360{\degree}}$

$\sf{ 253{\degree}+ 107 {\degree} = 360{\degree}}$

$\sf{ 253{\degree}+ 107 {\degree} = 360{\degree}}$

$\bold{ 360{\degree} = 360{\degree}}$

$\bold{ LHS = RHS }$

Hence, Proved.

8 0

2 years ago

Solve the system of equations by graphing. If the system has no solution or infinitely many so state.

S_A_V [24]

The systems will intersect at (1,-4), and i think the system has infinite solutions (not sure)

6 0

3 years ago

Very easy math anyone can do it

inn [45]

I would say A and C.

4 0

3 years ago

Can someone reply ASAP pls!!!!

ale4655 [162]

Answer:

the answer is 28

Step-by-step explanation:

the right angle=90

90-62=28

7 0

3 years ago

Read 2 more answers

What is the answer for y=−16x^2 +119x +73

Zina [86]

Answer:

Im pretty sure the answer is y=375x+73

Im not really sure

6 0

3 years ago