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viktelen [127]
3 years ago
12

I don’t know what this means or is

Mathematics
1 answer:
son4ous [18]3 years ago
6 0
It's Pythagoras theorem.......
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1. A calculator has a regular price of $59.95 before taxes.
777dan777 [17]
The answer is A 11.99
6 0
3 years ago
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Please help meeeeeeeeeeeeeeee!!!!!!!!!!!!!!
Ipatiy [6.2K]
Since the model is 1/13 the size of the tent, you multiply 6” by 13 to get 78”. Since you want feet, you divide 78” by 12” because there are 12 inches in a foot and you want to convert the unit to feet. The answer is 6.5 feet or 6.5’
4 0
3 years ago
How do you solve simple linear equations?
Firlakuza [10]

9514 1404 393

Explanation:

The rules of equality tell you that you can do anything you like to an equation, as long as you do the same thing to both sides of the equal sign. This is the essence of Algebra, so is worth remembering. My teacher summarized it as "keep the equal sign sacred."

__

"Simple linear equations" come in several varieties. They are sometimes called "one-step", or "two-step", or "three step" linear equations, depending on how many steps are required to solve them. In what follows, we're using "x" as the variable, and the letters a, b, c, d as constants.

<u>One-step</u>

In general, the "one step" will be either an addition or a multiplication.

  x + a = b . . . . an addition equation

  ax = b . . . . . . a multiplication equation

The key in any case is to look at what is done to the variable and use an inverse operation to "undo" it. The opposite of addition is addition of the additive inverse (add the opposite). This is also called subtraction. For the addition equation, this looks like ...

  x + a - a = b - a . . . . . . add (-a) <em>to both sides </em>(or subtract 'a')

  x = b - a . . . . . . . . . . . the solution

The opposite of multiplication is multiplication by the multiplicative inverse (the reciprocal) This is also called division. For the multiplication equation, this looks like ...

  ax(1/a) = b(1/a) . . . . . multiply by (1/a) <em>on both sides</em> (or divide by 'a')

  x = b/a . . . . . . . . . . . the solution

__

<u>Two-step</u>

As with one-step linear equations, two-step equations come in some different forms.

  ax +b = c

  ax +b = cx

  a(x +b) = c

In general, the two steps are an addition step and a multiplication step, not necessarily in that order. You will notice that the first step can transform the equation to a "one-step" equation. As before, inverse operations are involved, and whatever is done is done to both sides of the equal sign.

  ax +b = c   ⇒   ax = (c -b) . . . . subtract b to get a multiplication equation

In this next, we have the variable on both sides of the equal sign. we can put the variable on one side of the equal sign by adding the opposite of the term we don't want where it is. Leaving the constant alone, we can add (-ax) to both sides to get ...

  ax +b = cx   ⇒   b = cx -ax   ⇒   b = (c -a)x

When you have numbers, you can go directly to (c-a)x by "combining terms". This is now the one-step multiplication equation.

Finally, another 2-step form is ...

  a(x +b) = c   ⇒   x +b = c/a . . . . . divide by 'a' to get an addition equation

This last equation can also be solved by using the distributive property first.

  ax +ab = c . . . . . still a 2-step equation, now of the first type

__

<u>Three-step</u>

The most typical "3-step" linear equation is of the form ...

  ax +b = cx +d

where both variables and constants are on both sides of the equal sign. As you may have noticed above, we prefer to have variables on one side and constants on the other side. So, add the opposite of the term you don't want where it is (to both sides, of course).

If we want variables on the left and constants on the right, we can add -cx and -b. The "3 steps" assume you do these as separate operations.

  ax +b -cx = cx +d -cx   ⇒   (a-c)x +b = d . . . a two-step equation

  (a-c)x +b -b = d -b    ⇒   (a-c)x = d-b . . . . a one-step multiplication equation

_____

<em>Additional comments</em>

There are some choices you can make that will tend to reduce errors. One of them involves selection of the variable term you want to eliminate (add the opposite of). Generally, if you choose the term with the lowest (most negative, left-most on the number line) coefficient, adding its opposite will result in a positive coefficient for the remaining variable term. Then when you divide by that coefficient, you're dividing by a positive number. Most folks perform arithmetic with fewer errors when they're working with positive numbers.

The general approach to any "solve for" situation is to look at what is done to the variable you're solving for. The Order of Operations is a useful lens for looking at this. When you list the operations, your "undo" sequence will start with the last operation on the list, and work backward.

<em>Further note</em>: your total comfort with doing arithmetic with any kind of numbers (integers, fractions, mixed-numbers, decimals, scientific notation, positive or negative) will aid you immensely. Always be careful with minus signs. They tend to get lost, forgotten, ignored, Be sure they don't.

8 0
3 years ago
According to the rules of exponents, when u multiply powers, u ____ the exponents
7nadin3 [17]

Answer:

When you multiply powers you add the exponents together. (The first one's answer)

And when you raise a power to a power, you multiply them together. (The second one's answer)

Step-by-step explanation:

Because that's how you do it.

4 0
3 years ago
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Which of the following is the surface area of the right cylinder below?
Evgen [1.6K]
The formula for the surface area of a right cylinder is 2πrh + 2πr^2. r is the radius, and h is the height.


In this instance, the radius is 4, so plug that in for r. (I.E. Replace r with 4).


The formula is now 2π4h + 2π4^2.


Next, plug in the height, 8 for h.



Now we have 2π4(8) + 2π4^2, which is approximately 301.59.


The surface area is 301.59. (Unit of measure was not specified)



Hey Braniac! Thanks for your question! Don't forget to rate and give me the brainliest answer! Then, I can help you with all your problems! ^-^ ~

5 0
3 years ago
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