<span>An actor invested some money at 9% simple interest, and $42,000 more than three times the amount at 12% per annum. </span><span>What we are after is amounts of interest invested at 9% and at 12%. Let's call them x and y respectively.
x=42000 at 9% = </span>$3,780.00 = $45,780.00
y=3x42000 at 12% = $15,120.00 = $141,120.00
x+y=$186,900.00
Answer:
The area of ∆DEF = 4.5in²
Step-by-step explanation:
From the above diagram,
∆BAC ~∆DEF
It is important to note that if two triangles are similar, the ratio of their areas is equal or equivalent to the ratio of the areas of their sides
This means for the above question, that
We have the bigger triangle = ∆BAC has a side of 4 in and Area = 8 in²
The small triangle has a side of 3in
Finding the scale factor k = ratio of the sides of both Triangles
k = 4/3
k² = (4/3)²
k² = 16/9
Hence,
Area of ∆BAC/ Area of ∆DEF = 16/9
8in²/Area of ∆DEF = 16/9
We cross Multiply
8 in² × 9 = Area of ∆DEF × 16
Divide both sides by 16
Area of ∆DEF = 72/16
= 4.5in²
Therefore, the Area of ∆DEF rounded to the nearest tenth = 4.5in²
Answer:
64x2 ? 64x +16
Step-by-step explanation:
Answer: x = 0; x=10
Step-by-step explanation:
Hope this helps!
Answer:
C.
Step-by-step explanation:
