Answer:
Step-by-step explanation:
The system of equations is given as
y=x^2-5x+7 - - - - - - - - - - 1
y=2x+1 - - - - - - - - - - - - - - 2
We would equate equation 1 to equation 2, it becomes
x^2-5x+7 = 2x+1
x^2-5x+7- 2x - 1 = 0
x^2-5x+7- 2x - 1 = 0
x^2 - 5x - 2x + 7 - 1 = 0
x^2 - 7x + 6 = 0
We would use the factorization method of solving quadratic equations.
x^2 - 6x - x + 6 = 0
x(x - 6) - 1(x - 6)
(x - 6)(x - 1) = 0
x - 6 = 0 or x - 1 = 0
x = 6 or x = 1
Substituting both values of x into equation 2, it becomes
For x = 6,
y=2×6 + 1 = 12 + 1 = 13
y = 13
For x = 1,
y=2 × 1 +1 = 2 + 1 = 3
y = 3
Answer:
65
Step-by-step explanation:
they're going by 5s every time her score increases. hope I helped (:
=Y2-10Y
We move all terms to the left:
-(Y2-10Y)=0
We add all the numbers together, and all the variables
-(+Y^2-10Y)=0
We get rid of parentheses
-Y^2+10Y=0
We add all the numbers together, and all the variables
-1Y^2+10Y=0
a = -1; b = 10; c = 0;
Δ = b2-4ac
Δ = 102-4·(-1)·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
Y1=−b−Δ√2aY2=−b+Δ√2a
Δ‾‾√=100‾‾‾‾√=10
Y1=−b−Δ√2a=−(10)−102∗−1=−20−2=+10
Y2=−b+Δ√2a=−(10)+102∗−1=0−2=0
NO
no integers are considered irrational numbers.
ANSWER
The solution is 
EXPLANATION
We want to solve the simultaneous equations
and
.
We substitute equation (2) in to equation (1), to obtain
This has now become a linear equation in a single variable 
.
We solve for x by grouping like terms.
We divide through by negative 3 to get;
.
Hence, the solution is
