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Colt1911 [192]
4 years ago
13

(2×100)+(9×10)+(6×1)+(3×1/10)+(8×1/100)= In standard form

Mathematics
1 answer:
Sidana [21]4 years ago
5 0
We know that standard form = the number that is not expanded.
This equation is expanded so standard form =

2*100=200
9*10=90
6*1=6
3*1/10= 0.3
8*1/100=0.08

200+90=290
290+6=296
296+0.3=296.3
296.3+0.08=296.38

Your answer is 296.38
Hope this helped!
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On a coordinate plane, the coordinates of vertices R and T for a polygon are R(−6, 2) and T(1, 2). What is the length of Side RT
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4 0
3 years ago
The initial size of the population is 300. After 1 day the population has grown to 800. Estimate the population after 6 days. (R
Cloud [144]

Solution :

Given initial population = 300

Final population after 1 day = 800

Number of days = 6

∴ $\frac{dP}{dt} =kt^{1/2} $

P(0) = 300    P(1) = 300

We need to find P(8).

$dP = kt^{1/2} dt$

$ \int 1 dP = \int kt^{1/2} dt$

$P(t) = k \left(\frac{t^{3/2}}{3/2}\right)+c$

$P(t)= \frac{2k}{3}t^{3/2} + c$

When P(0) = 300

$300 = \frac{2k}{3} (0)^{3/2} + c$

∴ c = 300

∴ $P(t)= \frac{2k}{3}t^{3/2} + 300$

When P(1) = 800

$800 = \frac{2k}{3} (1)^{3/2} + 300$

$500 = \frac{2k}{3}$

∴ k = 750

$P(t)= 500t^{3/2} + 300$

So, P(8) is

$P(t)= 500(8)^{3/2} + 300$

        = 11,614

So the population becomes 11,614 after 8 days.

8 0
3 years ago
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