Using the normal distribution, it is found that 1851 people would have an IQ less than 115.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean
and standard deviation
is given by:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
The mean and the standard deviation are given, respectively, by:
![\mu = 100, \sigma = 15](https://tex.z-dn.net/?f=%5Cmu%20%3D%20100%2C%20%5Csigma%20%3D%2015)
The proportion of IQ scores less than 115 is the <u>p-value of Z when X = 115</u>, hence:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![Z = \frac{115 - 100}{15}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7B115%20-%20100%7D%7B15%7D)
Z = 1
Z = 1 has a p-value of 0.8413.
Out of 2200 people:
0.8413 x 2200 = 1851.
More can be learned about the normal distribution at brainly.com/question/27643290
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I believe it's A but it's not exactly clear
The answer is between B and C but... I'm kinda leaning more towards B but, you choose which one you think is right.
Hope I helped you. :)
Answer:
b
Step-by-step explanation:
Since both of the numbers have a variable which is x ready to be multiplied, there is no expression leading to the variable therefore you will add normally but you will need to put the missing variable which needs to be multiplied. So overall you can just add and once you get your variable you can be abe to multiply and get your final answer.
Hope this helps