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2 years ago

Using the figure below, find the lengyh of x.

Mathematics

1 answer:

katrin [286]2 years ago

5 0

Answer:

what i don't understand why you are not answer that question

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Find the distance that the points is given on the graph ?

EleoNora [17]

From the graph, the given points are (2,-1) and (4,0). Use the distance between two points formula:

$\large \boxed{ \sqrt{ {(x_2 - x_1)}^{2} + {(y_2 - y_1)}^{2} } }$

Substitute these points in the formula.

$\large{ \sqrt{ {(2 - 4)}^{2} + {( - 1 - 0)}^{2} } } \\ \large{ \sqrt{ {( - 2)}^{2} + {( - 1)}^{2} } } \\ \large{ \sqrt{4 + 1} \longrightarrow \sqrt{5} }$

Hence, the distance is √5

Answer

√5

7 0

2 years ago

A school principal ordered 1,000 pencils. He gave an equal number to each of 7 teachers until he had given out as many as possib

Semenov [28]

1000/7 = <span>142.857142857

Because this is not an even number we take "142", then times it by 7 teachers.

142*7= 994

1000 - 994 = 6 Pencils left</span>

3 0

3 years ago

Andrea and sula ran a race on a track that was 100 meters long.When andrea crossed the finish line sula was exactly 5 meters beh

cestrela7 [59]

Andrea will be at 95 meters and Sula would win I think.

7 0

2 years ago

I need help PLEASE help mee

EastWind [94]

Answer:

Step-by-step explanation:

In order to convert 0.0004578, which is in decimal, to scientific notation, all we need to do in this case is to move our decimal point to the right till we arrive at the first number that is not a zero, and then eliminate all the zero.

In this case, we will have to move the decimal point 4 spaces to our right, which would mean our exponent would be negative. The number of decimal spaces we moved to our right would be the value of our exponent, which is -4 in this case.

Thus, we have:

$4.578 * 10^{-4}$

6 0

3 years ago

What are the real zeros of the function g(x) = x3 + 2x2 − x − 2?

Nat2105 [25]

Upon a slight rearrangement this problem gets a lot simpler to see.

x^3-x+2x^2-2=0 now factor 1st and 2nd pair of terms...

x(x^2-1)+2(x^2-1)=0

(x+2)(x^2-1)=0 now the second factor is a "difference of square" of the form:

(a^2-b^2) which always factors to (a+b)(a-b), in this case:

(x+2)(x+1)(x-1)=0

So g(x) has three real zero when x={-2, -1, 1}

4 0

2 years ago

Using the figure below, find the lengyh of x.​

Using the figure below, find the lengyh of x.