Answer:
Step-by-step explanation:
Arithmetic sequence:
Here a is the first term and d is the common difference.
⇒ 
------------(I)
⇒ a + 19d = 100 ---------(II)
Subtract equation (I) from (II)
(I1) a + 19d = 100
(II) a + 13d = 46
<u>- - -</u>
6d = 54
d = 54 ÷ 6
Substitute d = 9 in equation(I) and find 'a',
a + 13*9= 46
a + 117 = 46
a = 46 - 117
a = -71
= -71 + 18
= -53
= -71 + 54
= -17
= -71 + 9*n - 1 *9
= -71 + 9n - 9
= -71 - 9 + 9n
= - 80 + 9n
Answer:
Principal: $6,166.67
Principal: $5,200.00
Explanation:
<u><em>1. $6000 for 50 days at 20% p.a</em></u>
<u><em></em></u>
In 20% pa, pa means "per annum", i.e. "per year".
Assume simple interest:
Interest:
- Interest = Principal × number of days × annual rate / 360
- Interest = $6,000 × 50 × 20% / 360 = $166.67
Principal = principal + interest = $6,000 + $166.67 = $6,166.67
<u><em></em></u>
<u><em>2. $5000 for 5 months at 0.8% per month</em></u>
Assume, again, simple interest.
- interest: 0.80% per month
Interest:
- Interest = Principal × number of months × montly rate
- Interest = $5,000 × 5 × 0.80% = $200.00
Principal = principal + interest = $5,000 + $200.00 = $5,200
You can see that the accrued interests depend on the principal, the interest rate, and the time.
Answer:
10.75
Step-by-step explanation:
The cost of an adult ticket is £6 more than that of a child ticket, so will be shown by c+6.
Now, we are told that the cost of four child tickets and two adult tickets is £40.50, so we can put this in an equation and solve for c:
(c+6)+(c+6)+c+c+c+c=40.50
6c+12=40.50
6c=28.50
c=4.75
so, a childs ticket is 4.75
now to find the cost of an adult ticket you add 6,
4.75 + 6
= 10.75
Answer:
2
Step-by-step explanation:
The degree of the polynomial is the highest exponent of an expression. When more than one variable is present, its is the sum of exponents on one term in the expression.
The polynomial has terms xy, 3x^2, -7 and x. The term with the highest exponent sum is xy or 3x^2. Both have degree 2. The degree of the polynomial is 2.
I think that this an example of a paired t test. Since each student (subject) is given 2 treatments of the same material.
