Well...
<span>0.63 + 0.37 = 1.00
</span>I hope I was somewhat helpful~
Best Regards~ Sans
Answer:
The correct answer is option 3.
Step-by-step explanation:
Given : ΔPQR, QM is altitude of the triangle
PM = 8
MR = 18
To find = QM
Solution :
PR = 8 + 18 = 26
Let, PQ = x , QR = y, QM = z
Applying Pythagoras Theorem in ΔPQR
..[1]
Applying Pythagoras Theorem in ΔPQM
..[2]
Applying Pythagoras Theorem in ΔQMR
..[3]
Putting values of 
and 
from [2] and [3 in [1].
z = ±12
z = 12 = QM ( ignoring negative value)
The length of QM is 12.
Basically u evaluate it into (3⁶y⁵)² then use the properties of exponents to simplify to (729y⁵)² and then ur answer is 729²y¹⁰ or in other words, 3¹²•y¹⁰ so ur answer is B.
Point-slope form of a line: we need a point (x₀,y₀) and the slope "m".
y-y₀=m(x-x₀)
slope intercept form :
y=m+b
m=slope
If the line is parallel to y=2/3 x-0, the line will have the same slope, therefore the slope will be: 2/3.
Data:
(8,4)
m=2/3
y-y₀=m(x-x₀)
y-4=2/3(x-8)
y-4=2/3 x-16/3
y=2/3 x-16/3+4
y=2/3 x-4/3 (slope intercept form)
Answer: The equation of the line would be: y=2/3 x-4/3.
if we have the next slope "m",then the perendicular slope will be:
m´=-1/m
We have this equation: y=2/3 x+0; the slope is: m=2/3.
The perpendicular slope will be: m`=-1/(2/3)=-3/2
And the equation of the perpendicular line to : y=2/3 x+0, given the point (8,4) will be:
y-y₀=m(x-x₀)
y-4=-3/2 (x-8)
y-4=-3/2 x+12
y=-3/2x + 12+4
y=-3/2x+16
answer: the perpendicular line to y=2/3 x+0 , given the point (8,4) will be:
y=-3/2 x+16
