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serg [7]
2 years ago
10

I need to know the slope intercept form for this question

Mathematics
1 answer:
andrey2020 [161]2 years ago
7 0
I think it’s y= 2x + 3
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0.63 =1.00 0.634 plus what equals a dollar
katen-ka-za [31]
Well...
<span>0.63 + 0.37 = 1.00
</span>I hope I was somewhat helpful~

Best Regards~ Sans
7 0
3 years ago
Read 2 more answers
Help plz,BIG POINTS,also plz show me the steps as best as possible
Sidana [21]

Answer:

The correct answer is option 3.

Step-by-step explanation:

Given : ΔPQR, QM is altitude of the triangle

PM  = 8

MR = 18

To find = QM

Solution :

PR = 8 + 18  = 26

Let, PQ = x  , QR = y, QM = z

Applying Pythagoras Theorem in ΔPQR

PQ^2+QR^2=PR^2

x^2+y^2=(26)^2..[1]

Applying Pythagoras Theorem in ΔPQM

PM^2+QM^2=PQ^2

8^2+z^2=(x)^2..[2]

Applying Pythagoras Theorem in ΔQMR

MR^2+QM^2=QR^2

18^2+z^2=(y)^2..[3]

Putting values of x^2 and y^2 from [2] and [3 in [1].

8^2+z^2+18^2+z^2=(26)^2

2z^2=(26)^2-(8)^2-(18)^2

2z^2=288

z^2=144

z = ±12

z = 12 = QM ( ignoring negative value)

The length of QM is 12.

6 0
3 years ago
Please help me, please please help ASAP!!!
shtirl [24]
Basically u evaluate it into (3⁶y⁵)² then use the properties of exponents to simplify to (729y⁵)² and then ur answer is 729²y¹⁰ or in other words, 3¹²•y¹⁰ so ur answer is B.
6 0
3 years ago
Write the fraction 4/9 as an equivalent fraction with the given denominator 45​
slega [8]

Answer:

answer is in the picture

5 0
3 years ago
consider the line y= 2/3x-0. Find the equation of the line that is parallel to this line and passes through the point (8, 4).
tresset_1 [31]
Point-slope form of a line: we need a point (x₀,y₀) and the slope "m".
y-y₀=m(x-x₀)

slope intercept form :
y=m+b

m=slope

If the line is parallel to y=2/3 x-0, the line will have the same slope, therefore the slope will be: 2/3.

Data:
(8,4)
m=2/3

y-y₀=m(x-x₀)
y-4=2/3(x-8)
y-4=2/3 x-16/3
y=2/3 x-16/3+4
y=2/3 x-4/3  (slope intercept form)

Answer: The equation of the line would be: y=2/3 x-4/3.


if we have the next slope "m",then the perendicular slope will be:
m´=-1/m

We have this equation: y=2/3 x+0; the slope is: m=2/3.

The perpendicular slope will be: m`=-1/(2/3)=-3/2

And the equation of the perpendicular line to : y=2/3 x+0, given the point (8,4) will be:

y-y₀=m(x-x₀)
y-4=-3/2 (x-8)
y-4=-3/2 x+12
y=-3/2x + 12+4
y=-3/2x+16

answer: the perpendicular line to y=2/3 x+0 , given the point (8,4) will be:
y=-3/2 x+16
3 0
3 years ago
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