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Burka [1]
3 years ago
10

Mr. Hall deposited money into an account in which interest is compounded quarterly at a rate of 2.6%. How much did he deposit if

the total amount in his account after 4 years was $7160.06, and he made no other deposits or withdrawals?
Mathematics
1 answer:
Amanda [17]3 years ago
8 0
The formula of this equation would be x_{0}* 1.026^16 = 7,160.06
So from this equation we know that x_{0} =  \frac{7,160.06}{1.026^{16} }
Now we need to find the value of x, we need to multiply x_{0} * 1.026 16 times. Which will bring us to your answer. $4,748.53
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If cos⁡ x=−45, and 180° < x < 270°, what is tan⁡(2x)?
iVinArrow [24]

Tan2x =\frac{-24}{7}

<u>Step-by-step explanation:</u>

Here we have , cos x = -4/5 ( corrected as given -45 which is not possible ) ,

180° < x < 270° i.e. in third quadrant  . We need to find tan⁡(2x) . Let's find out:

⇒ Tan\alpha  = \frac{sin\alpha }{cos\alpha }

⇒ Tan\alpha  = \frac{\sqrt{1-(cos\alpha)^2} }{cos\alpha }

⇒ Tan\alpha  = \frac{\sqrt{1-(\frac{-4}{5})^2} }{\frac{-4}{5} }

⇒ Tan\alpha  = \frac{-5}{4}\sqrt{1-(\frac{16}{25}) }

⇒ Tan\alpha  = \frac{-5}{4}\sqrt{(\frac{25-16}{25}) }

⇒ Tan\alpha  = \frac{-5}{4}(\frac{3}{5}) }

⇒ Tan\alpha  = \frac{-3}{4} , since in third quadrant . Tan\alpha  = \frac{-3}{4} remains same .

Now , Tan2x = \frac{2tanx}{1-(tanx)^{2}}}

⇒ Tan2x = \frac{2tanx}{1-(tanx)^{2}}}

⇒ Tan2x = \frac{2(\frac{-3}{4})}{1-(\frac{-3}{4})^{2}}}

⇒ Tan2x = \frac{-3}{2}(\frac{16}{7})

⇒ Tan2x =\frac{-24}{7}

Therefore, Tan2x =\frac{-24}{7} .

5 0
4 years ago
Financial advisors recommend that a maximum of 22% of your monthly income be spent on vehicle expenses (total of car payment, ca
Brut [27]

Answer:

22.4

Step-by-step explanation:515+78+125=718

718/3200=22.4

The answer is-No

3 0
3 years ago
Finding an Indefinite Integral dx/x(lnx^2)^3
Y_Kistochka [10]

Step-by-step explanation:

Firstly, we'll try to simplify the integrand. By hint 1, we see that:

\ln(x^2) = 2\ln(x)

Simplifying the integrand gives us:

\frac{1}{8}\left(\frac{1}{x(\ln(x))^3}\right)

Next, by hint 2, we observe that:

\frac{d}{dx}\left(\ln(x)\right) = \frac{1}{x}

So this tells us to make the substitution: u = \ln(x)

Doing so gives us:

\int \frac{dx}{x(ln(x^2))^3} = \int \frac{du}{8u^3}, which should be trivial.

3 0
4 years ago
F(x) = 5x + 3; g(x) = 6x - 5 Find f/g.
IRISSAK [1]

Answer:

hello :

f(x) = 5x + 3; g(x) = 6x - 5 =

f/g = (5x+3)/(6x - 5)    .....6x - 5 ≠ 0      so : x ≠ 5/6



7 0
4 years ago
NEED HELP EDU!! WILL GIVE BRAINLEIST!<br> which graph of the cube root function f(x)=^3 √x?
Luden [163]

Answer:

C. f(x)=\sqrt[3]{-x} -1

Step-by-step explanation:

Consider graph of the parent function (red curve in attached diagram)

g(x)=\sqrt[3]{x}

First, multiply it by -1 to get function

h(x)=-\sqrt[3]{x}

Then translate the graph of the function h(x) 1 unit down, then you'll get the function

f(x)=-\sqrt[3]{x} -1\\ \\ \text{or}\\ \\f(x)=\sqrt[3]{-x} -1

The graph of the function f(x) is represented by the blue curve in attached diagram

5 0
4 years ago
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